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topjm [15]
3 years ago
14

Arthur drops a ball from a height of 81 feet above the ground. Its height, h, is given by the equation h = –16t2 + 81, where t i

s the time in seconds. For which interval of time is the height of the ball less than 17 feet?
Mathematics
2 answers:
Lorico [155]3 years ago
6 0

Answer:

Step-by-step explanation:

We are given the position function and need to find the value of t when h<17.

Create an inequality that represents this situation:

-16t^2+81 The "less than" sign makes this very specifically a conjunction problem as opposed to a disjunction. That's important to the solution. But we'll get there.

The simplest way to solve this is to subtract 81 from both sides:

-16t^2 then divide both sides by -16:

t^2>4 Notice now that the sign is facing the other way since we had to divide by a negative number. Now it's a disjunction. The solution set to this inequality is that t>2 or t<-2. First and foremost, time will never be negative, so we can disregard the -2. Even if that was t<2, the more time that goes by, the greater the time interval is, not the lesser. It's the "<" that doesn't make sense, not only the -2. The solution to this inequality is

t > 2 sec. That means that after 2 seconds, the height of the ball is less than 17 feet.

MariettaO [177]3 years ago
3 0

Answer:

A on edg

Step-by-step explanation:

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We conclude that the mean wedding cost is less than $30,000 as advertised.

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We are given the following data set:(in thousands)

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\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

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Mean =\displaystyle\frac{236100}{8} = 29512.5

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Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

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t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

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We fail to accept the null hypothesis and reject it.

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Step-by-step explanation:

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