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4 years ago

9

What is the circumference of this circle

2 answers:

sweet-ann [11.9K]4 years ago

6 0

P=pie
P•d= circumference
3p

Yakvenalex [24]4 years ago

3 0

Answer:

C = 9.42cm

Step-by-step explanation:

C = pi*d

C = 3.14 x 3 = 9.42

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What is 1/3 divided by 2/7 equal to

Contact [7]

1/3 / 2/7
The first thing you do is switch the 2 and the 7 around and change the sign to a times:
1/3 X 7/2

1 X 7 = 7
3 X 2 = 6

1/3 X 7/2 = 7/6

7/6 (which is an improper fraction) can we written as 1 1/6 (which is a mixed number).

The answer is 1 1/6

8 0

3 years ago

Read 2 more answers

Harman [31]

Answer:

False

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$

Given a line with m = $\frac{3}{4}$

Then the slope of the line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{\frac{3}{4} }$ = - $\frac{4}{3}$

4 0

4 years ago

Help please if you dont mind

Bumek [7]

Answer:

D)

Step-by-step explanation:

For every x, there can be only y.

A, B and C violate that.

8 0

3 years ago

How does the graph of y = 2 · 2x compare to the graph of the parent?

Likurg_2 [28]

This can be also written as y=-2x+2

First of all the - at the beginning = reflection across the x axis.

Then the first 2 is a vertical stretch of 2

the second 2 is a translation of 2 units up.

So

1.ref. across the x axis

2.vert. stretch of 2

3. translation of 2 units up

6 0

3 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

4 years ago