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Marrrta [24]
3 years ago
14

Annita, Gary, and Tara all run races. Annita has 7 less than 4 times the number of race medals as Tara. Gary has 13 more than 2

times the number of race medals as Tara. If Annita and Gary both have the same number of race medals, how many race medals, t, does Tara have?
Which equation correctly represents the situation above?
Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

4 t - 7  = 2 t+ 13  is the required equation.

The number of race medals Tara has is t = 20 medals.

Step-by-step explanation:

Let the number of medals Tara has = t medals

So, the number of medal Anita has  = 4( Medals of Tara) - 7

= 4t - 7

And the number of medals Gary has = 2 times (Medals of Tara) + 13

= 2(t)  + 13  = 2t + 13

Now, Annita and Gary has same number of medals.

⇒  4t - 7  = 2t+ 13

or, 4t - 2t  = 7 + 13

⇒ 2t  = 20

⇒ t = 20/2 = 10

or t = 10

Hence, the number of race medals Tara has is t = 20 medals

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Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?
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18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\

Step 2

find the volume of the sphere when radius= 5.1 ft

v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\

Step 3

Compare the Volumes to find the change

\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

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change=18.03 cubic feet

Have a great day.

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