Answer:
B and C
Step-by-step explanation:
vertical angles are angles that are opposite of each other when two lines cross. Vertical angles are congruent = they are equally large.
the angles listed in B and C are mirrored across either an imaginary or a directly visible line. and that makes them vertical angles.
Hi there!
If KLM is an isosceles triangle, then KM = LM.
4d - 13 = 12 - d
Solve for d. Add 'd' to both sides:
5d - 13 = 12
Add 13 to both sides:
5d = 25
Divide both sides by 5:
<u>d = 5 units.</u>
Answer:
n+24=x
Step-by-step explanation:
Answer:
√5.
Step-by-step explanation:
Tan A = 1/2 means that the right triangle containing angle A has legs of length 1 and 2 units. So the hypotenuse = √(1^2 + 2^2) = √5 (using the Pythagoras theorem). The side opposite to < A = 1 unit and the adjacent side = 2 (as tan = opposite / adjacent).
so cos A = adjacent / hypotenuse = 2/√5.
and sin A = opposite / hypotenuse = 1 / √5
cos A / sin A = 2/√5 / 1/ √5 = 2.
sin A / (1 + cos A) = 1/√5 (1 + 2/ √5)
= 1 / √5 ( (√5 + 2) /√5)
= 1 / (√5 + 2)
So the answer is:
2 + 1 /(√5 + 2).
We can simplify it further by multiplying top and bottom of the fraction by the complement of √5 + 2 which is √5 - 2.
2 + 1 / (√5 + 2)
= 2(√5 + 2) + 1 / (√5 + 2 )
= { 2(√5 + 2) + 1 } / (√5 + 2)
Multiplying this by √5 - 2 / √5 - 2 we get:
(2(5 - 4) + √5 - 2) / (5 -4)
= 2 + √5 - 2 / 1
= √5.
Answer:
A quarter 
of one lap of the track.
Step-by-step explanation:
Three students ran ran a relay and took turns running equal parts of the track.
The race was three-fourths of a lap long.
Let the length of one lap of the track=x
The length of the race
Since each of the students ran equal part,
Length run by each student
Therefore, each student ran a quarter of one lap of the track.
