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3 years ago

Rony is making banners for Family Fun Night. Each banner needs to be 4 yards long. How many banners can he make out of 48 feet?

1 answer:

5 0

All you have to do is 48 /4 = 12 so the answer is that he can make 12 banners altogether, if you need further explanation feel free to tell me!

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Find an explicit formula for the geometric sequence -40,-20,-10......

garik1379 [7]

Answer:

The explicit formula for the geometric sequence is $c(n) = -40\cdot \left(\frac{1}{2} \right)^{n-1}$ .

Step-by-step explanation:

By definition of geometric sequence, we should use the following expression:

$c(n) = c_{1}\cdot r^{n-1}$ , $n \ge 1$ (1)

Where:

$c_{1}$ - First term.

$r$ - Geometric rate.

$n$ - Position of the element within the series.

If we know that $c_{1} = -40$ and $r = \frac{1}{2}$ , then the explicit formula for the geometric sequence is:

$c(n) = -40\cdot \left(\frac{1}{2} \right)^{n-1}$

The explicit formula for the geometric sequence is $c(n) = -40\cdot \left(\frac{1}{2} \right)^{n-1}$ .

3 0

3 years ago

Antony is flipping a coin and rolling a standard number cube (dice).

Flura [38]

Theres a 50/50 chance

6 0

3 years ago

Read 2 more answers

89,000 rounded to the nearest thousand

Rufina [12.5K]

89 thousands?

........................

4 0

2 years ago

Read 2 more answers

I need help to get good grade

8090 [49]

Answer:

The scale factor is now 3

Step-by-step explanation:

6/2=3

12/4=3

The smaller square was increased by the scale factor of 3

5 0

3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago