By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
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Answer:
It's B. on EtDtGtE
Step-by-step explanation:
Answer:
160
Step-by-step explanation:
if 8 cans equal 1/4 of a pound. Then 5 pounds would be 20/4 pounds.
so 2×8=16
then 20×8=160
The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second
Step-by-step explanation:
We have to calculate his unit rate for both type of races
So,
<u>Unit rate for 400m race:</u>
Distance = 400m
Time = 43 sec
<u>Unit rate for 300m Race:</u>
Distance = 300m
Time = 31 sec
The difference between both unit rates is:
Hence,
The difference between both unit rates rounded off to the nearest tenth is: 0.4 meters per second
Keywords: Unit rate, Speed
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