Answer:
The speed of the boat in still water is 18 mph.
The speed of the current is 2 mph
Step-by-step explanation:
Let x constitute the charge of the boat in nonetheless water.
Let y constitute the rate of the contemporary.
When the boat is going against the modern-day, the rate is sixteen mph. Assuming it traveled against the modern at the equal time as going upstream, its general speed may be (x - y) mph. It way that
x - y = 16 (equation 1)
Going downstream, the boat averages 20 mph. Assuming it traveled with the current, its standard pace would be (x + y) mph. It way that
x + y = 20 (equation 2)
Adding each equation, it becomes
2x = 36
x = 36/2
x = 18 mph
Substituting x = 18 into equation 1, it will become
18 - y = 16
y = 18 - 16
y = 2 mph
#SPJ10
I’m pretty sure that your answer would be A: V = One-Third (6) (4) (8)
Hope this helps!!!
Just substitute t=t-2 in given function.
so, p(t-2)=4(t-2)-5
6x - 3y = 2,,,,this, paired with the other equation, will produce a system with one solution, which makes it consistent and independent.
Answer:
Step-by-step explanation:
Percent change = (Change/Original)
For Week 2 the % change is [(13.5-14)/14]*100%
For week 3 the % change is [(13.1-13.5)/13.5]*100%
Week Time(s) Change % Change
1 14
2 13.5 -0.5 -3.57%
3 13.1 -0.4 -2.96%
The negative value for percent change reflect the drop in time (an improvement, but not a positive number.