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const2013 [10]
3 years ago
9

Evaluate v(x) = 14 – 3x when x = -3,0, and 4.

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer: 23 , 14 , 2

Step-by-step explanation:

V(-3)=14-3(-3)

=14+9

=23

V(0)=14-3(0)

=14-0

=14

V(4)=14-3(4)

=14-12

=2

I hope this helps

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Find a degree 4 polynomial having zeros -8,-1,4 and 5 and the coefficient of x^4 equal 1.
Keith_Richards [23]

Answer:

  x^4 -53x^2 +108x +160

Step-by-step explanation:

If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...

  p(x) = (x +8)(x +1)(x -4)(x -5)

Multiplying these out gives the polynomial in standard form.

  = (x^2 +9x +8)(x^2 -9x +20)

We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.

  = (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)

  = x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160

  p(x) = x^4 -53x^2 +108x +160

_____

The graph shows this polynomial has the required zeros.

4 0
3 years ago
Value of m varies directly as value of n and n=5 when m=12. What is n when m=18?
ohaa [14]
Simplify the problem down, so:

m = 12 & n = 5
m = 6 & n = 2.5 <span>(divided each number by 20)
</span>
Now m is a factor of 18. Multiply each number by 3.
Answer: m = 18 & <span>n = 7.5</span>
6 0
3 years ago
Write the slope intercept equation of the function f whose graph satisifies the given conditions. The graph of f passes through
MrMuchimi
  • Let's find slope first.

  • (1,-2)
  • (-8,6)

\\ \sf\longmapsto m=\dfrac{6+2}{-8-1}

\\ \sf\longmapsto m=\dfrac{8}{-9}

Slope intercept form

\\ \sf\longmapsto y=mx+b

\\ \sf\longmapsto y=-\dfrac{8}{9}x-2

3 0
3 years ago
R is inversely proportional to A.
hjlf

Here are the answer: a) R = 3.6 and b) A = 2

Step-by-step explanation:

Given,

R is inversely proportional to A.

R ∝ \frac{1}{A}

so, R = \frac{k}{A}  -------eq 1 where k is any constant

To find the values of a) R when A = 5 and

b) Value of A when R = 9

Now,

Putting R = 12 and A = 1.5 in eq 1 we get,

12 = \frac{k}{1.5}

or, k = 12×1.5 = 18

From eq 1 we get,

R = \frac{18}{A} --------- eq 2

Now,

a) Putting A= 5 in eq 2 we get,

R = \frac{18}{5} = 3.6

b)  Putting R = 9 in eq 2 we get

R = \frac{18}{A}

or, A = \frac{18}{9} = 2

5 0
3 years ago
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Find the value of 35° 9 ​
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