Answer:
249m
Step-by-step explanation:
Answer:
Markup amount: $54
New price with markup: $204
Step-by-step explanation:
36% markup to $150
We can find the amount of markup by finding 36% of 150.
36% of $150
Write 36% as a decimal and multiply it by the price
0.36(150) = $54
The amount of markup (36%) is equal to $54
When this is added to the original price, the new price is $150 + $54 = $204
Let me know if you have any questions!
C.<span>She used an incorrect formula. The formula should be the change in </span>y<span>-values with respect to the change in the </span>x<span>-values.
</span>
Answer:
y=2x-8
just wondering: how does summer depend on this?!?!
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)