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1 year ago

For a polygon with 10 sides, which equation below represents the sum of the interior angles in the polygon?

Mathematics

1 answer:

jekas [21]1 year ago

3 0

The sum of the interior angles in the polygon whose side is 10 is $1440^{0}$

<h3>What is sum of interior angle of polygon ?</h3>

The sum of the interior angles in a regular polygon is given by the formula 180(n – 2), where n is the number of sides in the polygon.

As, The formula for calculating the sum of interior angles is ( n − 2 ) × $180^{0}$

S0, n=10

Then, sum of interior angle be = (n-2) x 180

= (10-2) x 180

= 8 x 180

$= 1440^{0}$

Thus, the sum of the interior angles in the polygon is $1440^{0}$

Learn more sum of interior angle of polygon here:

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Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

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The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

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A fraction is only 0 when it's numerator is 0. You are really just solving:

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Divide both sides by 2:

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The y-intercept is when x is 0.

Replace x with 0.

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$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

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x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

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So you can think it like this what value will y never be here.

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So y will never be 2+0=2.

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(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

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3 years ago

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larisa86 [58]

9514 1404 393

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2 years ago