Answer:
1. Scatter plots are used to observe relationships between variables. The position of each dot on the horizontal and vertical axis indicates values for an individual data point.
2. A Scatter Analysis is used when you need to compare two data sets against each other to see if there is a relationship. Scatter plots are a way of visualizing the relationship; by plotting the data points you get a scattering of points on a graph
Step-by-step explanation:
I am leaving the last two for someone else to have a chance to answer.
I hope my answers helped.
Answer:
The points for the given to linear equations is (5 , - 2) and (5 , - 1)
The points is plotted on the graph shown .
Step-by-step explanation:
Given as :
The two linear equation are
y = 
x - 1 ...........1
y = 
x - 6 ...........2
Now, Solving both the linear equations
Put the value of y from eq 2 into eq 1
I.e x - 6 = x - 1
Or, x + 
x = 6 - 1
Or, 
x = 5
or, 
x = 5
∴ x = 5
Now, Put the value of x in eq 1
So, y = x - 1
Or, y = × 5 - 1
or, y = 
- 1
Or, y = - 1 - 1
I.e y = -2
So, For x = 5 , y = - 2
Point is (
, 
) = (5 , - 2)
Again , put the value of x in eq 2
So, y = x - 6
Or, y = × 5 - 6
Or, y = 
- 6
Or, y = 4 - 6
I.e y = - 2
So, For x = 5 , y = - 2
Point is (
, 
) = (5 , - 2)
Hence, The points for the given to linear equations is (5 , - 2) and (5 , - 2)
The points is plotted on the graph shown . Answer
First, you want to establish your equations.
L=7W-2
P=60
This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.
60=2(7W-2+W)
Now that we only have 1 variable, we can solve.
First, distribute the 2.
60=14W-4+2W
Next, combine like terms.
60=16W-4
Then, add four to both sides.
64=16W
Lastly, divide both sides by 16
W=4
To find the length, we plug in our width.
7W-2
7(4)-2
28-2
L=26
We will solve this by suing simultaneous equations,
⇒ 5s + 3j = 87
4s + 2j = 64
Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,
⇒ (5s + 3j = 87) × 4
(4s + 2j = 64) × 5
∴ ⇒ 20s + 12j = 348
20s + 10j = 320
Subtract both the equations. This is how your result (after subtraction) should look like,
⇒ 2j = 28
∴ ⇒ j = $14
Now replace the value of 'j' in one of the original equations,
⇒ 4s + 2(14) = 64
⇒ 4s + 28 = 64
⇒ 4s = 64 - 28
⇒ 4s = 36
∴ ⇒ s = $9
Therefore, one pair of jeans cost $14 and a shirt costs $9
Hope you understood! Feel free to ask me if you didn't understand a step.
