Question

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia and older subjects before treatment 14 subjects had a mean weight time of 104.0 minutes after treatment the 14th subjects had a mean weight time of 95.9 minutes and a standard deviation of 24.4 minutes assume that the 14 sample values appear to be from a normally distributed population in construct a 99% confidence interval estimate of the mean weight time for a population with drug treatments

Answer 1

Answer:

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

Step-by-step explanation:

Step(i):-

Given data mean of the Population = 104 minutes

Given sample size 'n' =14

Mean of the sample(x⁻)  = 95.9 minutes

Given Standard deviation  = 24.4 minutes

Step(ii):-

99% confidence interval estimate of the mean weight time for a population is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} +Z_{0.01} \frac{S.D}{\sqrt{n} })$

$(95.9 - 2.576\frac{24.4}{\sqrt{14} } , 95.9+2.576\frac{24.4}{\sqrt{14} })$

On calculation , we get

(95.9 -16.79 , 95.9 +16.79)

(79.11 , 112.69)

Conclusion:-

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)