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3 years ago

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A clinical trial was conducted to test the effectiveness of a drug for treating insomnia and older subjects before treatment 14

subjects had a mean weight time of 104.0 minutes after treatment the 14th subjects had a mean weight time of 95.9 minutes and a standard deviation of 24.4 minutes assume that the 14 sample values appear to be from a normally distributed population in construct a 99% confidence interval estimate of the mean weight time for a population with drug treatments

1 answer:

RideAnS [48]3 years ago

7 0

Answer:

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given data mean of the Population = 104 minutes

Given sample size 'n' =14

Mean of the sample(x⁻) = 95.9 minutes

Given Standard deviation = 24.4 minutes

<u><em>Step(ii)</em></u>:-

99% confidence interval estimate of the mean weight time for a population is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} +Z_{0.01} \frac{S.D}{\sqrt{n} })$

$(95.9 - 2.576\frac{24.4}{\sqrt{14} } , 95.9+2.576\frac{24.4}{\sqrt{14} })$

On calculation , we get

(95.9 -16.79 , 95.9 +16.79)

(79.11 , 112.69)

<u><em>Conclusion:</em></u>-

99% confidence interval estimate of the mean weight time for a population with drug treatments

(79.11 , 112.69)

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Dennis_Churaev [7]

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The conjecture is that x = a + b. You should always find that to be true. C is the clincher.

Here's how you do that.

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Summary

a cannot be solved without 28

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