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3 years ago

Please find sin r please

Mathematics

1 answer:

LiRa [457]3 years ago

4 0

Sin r = 20/29

SOHCAHTOA

R:
(O) opposite - 20
(A) adjacent - 21
(H) hypotenuse - 29

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Can someone pls help with this

Gnom [1K]

here it is :)

do check properly, I have given step by step instructions:)

do give feedback on my answer, would appreciate it!

5 0

3 years ago

Read 2 more answers

A driver driving a business trip of 240 miles would have reached his destination if he'd been able to drive 12 mph faster than h

mariarad [96]

The average speed of his trip is = 12 mile/ hour

The total distance covered by the driver = 240 miles

The rate at which he traveled = 12 miles per hour

Therefore, the time he used to cover his distance

= 240/12

= 20 hrs

But average speed = distance/ time

= 240/ 20

= 12 miles/ hour

Therefore, the average speed of his trip is = 12 mile/ hour

Learn more here:

brainly.com/question/11753352

8 0

2 years ago

Water drains from a barrel at a constant rate. The graph and table show how the amount of water in the barrel changes with time.

lana66690 [7]

Answer:

Option C is correct.

Step-by-step explanation:

We have been given the graph

The graph is not of exponential function

Therefore, option A and B are discarded.

Now, We can see the graph is starting from 37

And the difference between Amount of water from the table is 19-22 that is -3

So, the graph is arithmetic

So, applying the formula $a_n=a+(n-1)d$ ; d is common difference here we have d= -3

$a(n)=37-3(n-1)$

Therefore, option C is correct.

3 0

3 years ago

- 4/9 times - 5/8 in fractions.

omeli [17]

Answer:

5/8 x 4/9 = 20/72 as simplified as 5/18 in fraction form. 5/8 x 4/9 = 0.2778 in decimal form.

Step-by-step explanation:

5 0

3 years ago

Preview Activity 3.5.1. A spherical balloon is being inflated at a constant rate of 20 cubic inches per second. How fast is the

ArbitrLikvidat [17]

Answer:

The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.

Because $\frac{dr}{dt}=\frac{5}{36\pi }>\frac{dr}{dt}=\frac{5}{64\pi }$ the radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Let $r$ be the radius, $d$ the diameter, and $V$ the volume of the spherical balloon.

We know $\frac{dV}{dt}=20 \:{in^3/s}$ and we want to find $\frac{dr}{dt}$

The volume of a spherical balloon is given by

$V=\frac{4}{3} \pi r^3$

Taking the derivative with respect of time of both sides gives

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

We now substitute the values we know and we solve for $\frac{dr}{dt}$ :

$d=2r\\\\r=\frac{d}{2}$

$r=\frac{12}{2}=6$

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=\frac{20}{4\pi(6)^2 } =\frac{5}{36\pi }\approx 0.044$

The radius is increasing at a rate of approximately 0.044 in/s when the diameter is 12 inches.

When d = 16, r = 8 and $\frac{dr}{dt}$ is:

$\frac{dr}{dt}=\frac{20}{4\pi(8)^2}=\frac{5}{64\pi }\approx 0.025$

The radius is increasing at a rate of approximately 0.025 in/s when the diameter is 16 inches.

Because $\frac{dr}{dt}=\frac{5}{36\pi }>\frac{dr}{dt}=\frac{5}{64\pi }$ the radius is changing more rapidly when the diameter is 12 inches.

8 0

3 years ago