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KatRina [158]
3 years ago
12

The equation 22 = 2y + x represents the perimeter of a flower garden with

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

y =  \frac{22-x}{2}

For width = 2 ft, the length of the flower bed = 10 ft.

For width = 3 ft, the length of the flower bed = 9.5 ft.

For width = 4 ft, the length of the flower bed = 9 ft.

Step-by-step explanation:

Here, the Perimeter of the flower garden is given as

22 = 2 y + x

: where, y : Length of the garden

and x : Width of the garden .

Now, solving for y in the above expression,we get

22 = 2 y + x  ⇒    22 - x = 2 y

or, y =  \frac{22-x}{2}

Now, <u>when the width (x) = 2 feet</u>

Length of the flower  bed y =  \frac{22-x}{2}  = \frac{22-2}{2}  = \frac{20}{2}  = 10

or, x = 10 ft

⇒For, the width = 2 ft, the length of the flower bed = 10 ft.

<u>when the width (x) = 3 feet</u>

Length of the flower  bed y =  \frac{22-x}{2}  = \frac{22-3}{2}  = \frac{19}{2}  = 9.5

or, x = 9.5 ft

⇒For, the width = 3 ft, the length of the flower bed = 9.5 ft.

<u>when the width (x) = 4 feet</u>

Length of the flower  bed y =  \frac{22-x}{2}  = \frac{22-4}{2}  = \frac{18}{2}  = 9

or, x = 9 ft

⇒For, the width = 4 ft, the length of the flower bed = 9 ft.

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3.1 Find the equation of the line passing through (4, 5) and parallel to the line 3x – 2y = 4.
valentinak56 [21]

                   \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

            <em>Find the equation of the line passing through (4, 5) and parallel to </em>

<em>                 3x-2y=4.</em>

<em />

<em>  </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

\rightarrow First, add 2y on both sides:-

                            \Large\textsf{3x+2y=4}

\rightarrow Now, subtract 3x on both sides:-

                  \Large\textsf{2y=-3x+4}

\rightarrow Divide by 2 on both sides

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\rule{300}{3}

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\hookrightarrow\sf{y-y_1=m(x-x_1)}

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\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}

\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}

<h3>Good luck with your studies.</h3>

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Greetings,
n00nst00p :)
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