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I have 7200 bags of snickers. If the rest is Hershey’s and Twix is 2/3 of snickers, how many Hershey’s are there?

AveGali [126]

Answer:

Step-by-step explanation:

You have 7,200 bags of snickers

Twix is 2/3 that of snickers

Hershey's is ?

First you need to find out how much Twix you have.

You will need to multiply as a fraction: 2/3*7,200/1 (2 over 3 multiplied by 7,200 over 1)

Next multiply the two numerators together (numerators are the numbers on top of a fraction and the numbers on the bottom of the fraction are called denominators)

2 * 7,200 = 14,400

Next multiply the denominators together:

3 * 1 = 3

So now your fraction is 14,400/3 (14,400 over 3)

Now divide the denominator into the numerator:

14,400 divided by 3 = 4,800

So 2/3 of the 7,200 bags of Snickers equals 4,800 Twix

Now take away the Twix from the Snickers

7,200 - 4,800 = 2,400

So now all up you have:

7,200 bags of snickers

4,800 bags of Twix

2,400 bags of hershey's

=)

4 0

1 year ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Is this table proportional or non-proportional?

tatyana61 [14]

Answer:

in my opinon, this table is proportional

5 0

2 years ago

Which number is missing from the following prime factorization expression? 792 = __ x 2 x 2 x 2 x 3 x 11 A. 2 B. 3 C. 5 D. 7

lions [1.4K]

Answer:

3

Step-by-step explanation:

Evaluate 2 x 2 x 2 x 3 x 11 (better written as 2·2·2·3·11, because "x" is a variable name, not a math operator).

2·2·2·3·11 = 8·33 = 264

Then divide 792 by this 264 to find the final factor:

final factor = 792/264 = 3

Then the prime factorization of 792 is 2·2·2·3·3·11

which we obtained by multiplying 2 x 2 x 2 x 3 x 11 by 3.

7 0

2 years ago

Read 2 more answers

Ellen claims she has a coin that is weighted so that the probability of heads is 70%.

kvasek [131]

<span>Outcome Heads Tails
Relative Frequency 0.69 0.31

so first statement is false as 69% is close to 70%.

second statement is false as heads probability is close to 70%

last 2 statements are true:

</span><span>The theoretical probability of tails is most likely 30%.

It is likely that the coin is not fair.
</span>

5 0

2 years ago

Read 2 more answers