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3 years ago

Helppppppp pllzzzzzzz

Mathematics

1 answer:

torisob [31]3 years ago

5 0

I can't answer this because I don't know what she was starting with

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The critical value t* gets larger as the confidence level increases. True or false?

posledela

Answer:

We can find the critical value $t_{\alpha/2}$

And for this case if the confidence increase the critical value increase so then this statement is True

Step-by-step explanation:

For a confidence level given c, we can find the significance level like this:

$\alpha=1 -c$

And with the degrees of freedom given by:

$df=n-1$

We can find the critical value $t_{\alpha/2}$

And for this case if the confidence increase the critical value increase so then this statement is True

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3 years ago

How many times does 4 go into 78

Bess [88]

You would do 78/4 which equals 19.5. Hope this helps!

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3 years ago

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I need a little help on 21

lidiya [134]

Answer:

560 seconds.

Step-by-step explanation:

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3 years ago

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2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

3 years ago

If the distance between A(0, 4) and B(3,a) is 5 units then find the value of a.

Anna007 [38]

Answer:

Step-by-step explanation:

a = 0

So that AOB makes a right triangle with sides 3-4-5

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2 years ago

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