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2 years ago

Enter the correct 9 letter sequence (no space) use all capital letters

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

6 0

Answer:

i think you forgot the rest of the question?

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1/3x+4=x-2<br><br><br> SHOW WORK

Len [333]

X= -3
I hope that helps :)

8 0

2 years ago

How do i figure out 9 1/6 - 8 5/6<br> and 10 3/4 - 6 4/4?

Westkost [7]

Answer:

1) $9\frac{1}{6}-8\frac{5}{6}=\frac{1}{3}$

2) $10\frac{3}{4}-6\frac{4}{4}=3\frac{3}{4}$

Step-by-step explanation:

You can convert he mixed numbers to improper fractions:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained to the numerator.

3. The denominator does not change.

Then:

$9\frac{1}{6}=\frac{54+1}{6}=\frac{55}{6}\\\\8\frac{5}{6}=\frac{48+5}{6}=\frac{53}{6}\\\\10\frac{3}{4}=\frac{40+3}{4}=\frac{43}{4}\\\\6\frac{4}{4}=\frac{24+4}{4}=\frac{28}{4}$

Observe that, in each subtraction, the denominators are equal, then you can rewrite the denominator and subtract the numerators:

$1)\ \frac{55}{6}-\frac{53}{6}=\frac{55-53}{6}= \frac{2}{6}=\frac{1}{3} \\\\2)\ \frac{43}{4}-\frac{28}{4}=\frac{43-28}{4}= \frac{15}{4}$

Divide 15 by 4. The quotient will be 3 and the remainder 3.

Then:

$\frac{15}{4}=3\frac{3}{4}$

6 0

2 years ago

Kaylin buys a greeting card for $3.79. she then buys 4 postcards that all cost the same amount. the total cost is $5.11. how muc

Pie

Answer:

Step-by-step explanation:

Givens

Greeting Card = 3.79

Total Cost = 5.11

Post cards = x

Equation

Total Cost = Greeting Card + 4x

Solution

Substitute the gives into the equation

5.11 = 3.79 + 4x Subtract 3.79 from both sides

5.11 - 3.79 = 3.79 - 3.79 + 4x Combine

1.32 = 4x Divide by 4

1.32/4 = 4x/4

x = 33

Each post card costs 0.33 dollars

4 0

1 year ago

A space S is defined as S = {1, 3, 5, 7, 9, 11} , and three subsets as A = {1, 3, 5} , B = {7, 9, 11} , C = {1, 3, 9, 11} . Assu

Lina20 [59]

Answer:

a) 0.5

b) 0.5

c) 0.67

d) 1

e) 0.83

f) 0.67

Step-by-step explanation:

P(A)=n(A)/n(S)

n(A)=number of outcomes in event A=3

n(S)= Total number of outcome of an experiment=6

P(A)=3/6=1/2=0.5

P(B)=n(B)/n(S)

n(B)=number of outcomes in event B=3

P(B)=3/6=1/2=0.5

P(C)=n(C)/n(S)

n(C)=number of outcomes in event C=4

P(C)=4/6=2/3=0.67

A∪B= {1,3,5} ∪ {7,9,11}={1,3,5,7,9,11}

P(A∪B)=n(A∪B)/n(S)=6/6=1

A∪C={1,3,5}∪{1,3,9,11}={1,3,5,9,11}

P(A∪C)=n(A∪C)/n(S)=5/6=0.83

A-C={1,3,5}-{1,3,9,11}={5}

(A-C)∪B={5}∪{7,9,11}={5,7,9,11}

P((A-C)∪B)=n((A-C)∪B)/n(S)=4/6=2/3=0.67

8 0

3 years ago

I need help with this thanks!!!!!

mixas84 [53]

Is this supposed to be a matching game of some sort? If so, I don’t think any of these here match what’s in the tables.

Sorry :(

8 0

2 years ago