Step-by-step explanation:
On the verge of troll, this question is.
"Two" : 2
"minus": -
"y" : y
2-y
Answer:
B ±sqrt((y-k)/a ) + h= x
Step-by-step explanation:
y=a(x-h)^2+k
Subtract k from each side
y-k = a(x-h)^2+k-k
y-k = a(x-h)^2
Divide by a
(y-k)/a = a(x-h)^2/a
(y-k)/a = (x-h)^2
Take the square root of each side
±sqrt((y-k)/a )= sqrt((x-h)^2)
±sqrt((y-k)/a )= (x-h)
Add h to each side
±sqrt((y-k)/a ) + h= (x-h+h)
±sqrt((y-k)/a ) + h= x
The first on is the tenth place
the second one is the tenth place
the third one is the tenth place
the last one is the millionth place
hope i helped :) i might be wrong though
Since it's negative you just go clockwise instead of counterclockwise around the circle. One full revolution is -6pi/3, two revolutions are -12pi/3, three would be -18pi/3. This tells you it's pi/3 shy of being 3 full revolutions sin -17pi/3 would be the same as pi/3.
Sin pi/3= 1/2
Reflection over the y-axis:
(x, y) ⇒ (-x, y)
Reflection of that over the line y = x:
(-x, y) ⇒ (y, -x)
Rotation counterclockwise by 270°:
(x, y) ⇒ (y, -x) . . . . . . equivalent to reflection over y, then over y=x.
The appropriate choice is ...
C) Reflecting over the y-axis and then reflecting over the line y = x.