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Nataly [62]
3 years ago
11

A man standing at point A walks 1 mile south, 3 miles east, 5 miles north, and 7 miles west to reach point B. The length of line

segment
AB is
A. 4 miles
B. √8 miles
C. 2 miles
D. √32miles
E. √12 miles
Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer: √32

Step-by-step explanation: so the displacement is north 4 and west 4 and it becomes a right triangle so the hypotenuse is the distance for segment AB

So Drawn out should like straight lines up,down,left,and right. So east is positive while west is negative same for North(+) and South(-)

I recommend sticking with 2 directions first. Starting with north and south right. First you go south 1 mile but then you go north 5miles in math terms

-1+5=4 or down one is one less than 5

Same for east and west. 3+-7 = -4

So we went positive 4 miles up and 4miles to the left

So (-4)^2+4^2= hypotenuse or AB segment in this case

Download pdf
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It says solve by factoring.
dsp73

Answer:

Alright well Graph each side of the equation. The solution is the x - value of the point of intersection k = 4.582 Hope this helps :)

Step-by-step explanation:


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Answer:

answer is c.

Step-by-step explanation:

the graph crosses the y-axis at (0,5) , increasing from x=-10 to x=2 and decreasing from x=2 to x=10

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One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the
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Let's call the two numbers s and l.


Given these variables, we can say: s = l - 14, based on the first sentence in the problem.


Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}


To solve, we can simply substitute l -14 in for s in the second equation and solve.

\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}

  • Set up

\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}

  • Get terms on the left side to a common denominator for easier addition

\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}

  • Simplify

4(6l - 70) = l(l - 14)

  • Cross multiplication (\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc)

24l - 280 = l^2 - 14l

  • Simplify

l^2 - 38l + 280 = 0

  • Subtract 24l - 280 from both sides of the equation

(l - 10)(l - 28) = 0

  • Factor left side of the equation

l = 10, 28

  • Zero Product Property

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,

s = 10 - 14 = -4,

Since s is not positive in this case, l = 10 is not a solution.


Thus, l = 28 is our only solution. In this case,

s = 28 - 14 = 14,

which means that the smaller number is 14 and the larger number is 28.

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Answer:

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Step-by-step explanation:

(a) If RS = x, then the sum of arcs around the circle is ...

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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°

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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...

  ∠UTS = 120°/2 = 60°

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