Answer:
116.7 Hz
Explanation:
Let there are two wires A and B.
Tension in wire A = T
Tension in wire B = 2T
Length of wire A = L
Length of wire B = 2L
fundamental frequency in wire A, fA = 330 Hz
let the fundamental frequency in wire B is fB.
The formula for the fundamental frequency is given by
where, μ is the mass per unit length
mass per unit length of wire A = Area of wire A x density
mass per unit length of wire B = Area of wire B x density
So,
fB = 330 / 2.828
fB = 116.7 Hz
Thus, the frequency in the second wire is 116.7 Hz.
The sources of the waves must be coherent, which means they emit identical waves with a constant phase difference and the waves should be monochromatic - they should be of a single wavelength.
~Sanjith U.
Answer:
<em><u>Hypothesis #2 If an earthworm is exposed to a strong odor, then it will back away from the odor because it will think that the odor is a sign of danger. ... Second, you will test earthworms' response to dry conditions by providing both a dry surface and a moist surface for the earthworms to crawl on.</u></em>
Answer:
a) C = 4,012 10⁻¹⁴ F, b) Q = 1.6 10⁻¹¹ C
, c) U = 3.21 10⁻¹¹ J
Explanation:
a) The capacitance of a capacitor is
C = k e₀ A / d
Let's calculate
C = 4 8.85 10⁻¹² 17 10⁻⁴ / 0.150 10⁻²
C = 4,012 10⁻¹⁴ F
b) let's look the charge
C = Q / ΔV
Q = C ΔV
Q = 4,012 10⁻¹⁴ 400
Q = 1.6 10⁻¹¹ C
c) The stored energy
U = ½ C ΔV²
U = ½ 4,012 10⁻¹⁴ 400²
U = 3.21 10⁻¹¹ J