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damaskus [11]
3 years ago
6

What are 3 types of contact forces

Physics
2 answers:
Andrej [43]3 years ago
6 0
FRICTION, TENSION, AND REACTION FORCE
Svetach [21]3 years ago
5 0

There are different types of contact forces like normal Force, spring force, applied force and tension force.

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3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?​
Dovator [93]

Answer:

3,200,000,000 J

Explanation:

Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation

W=Fs

where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the <em>displacement </em>(in meters).

Here, we have F = 1,600,000 N and s = 2000 m, so our work will be

W=1.600.000(2.000)=3.200.000.000 J

7 0
3 years ago
To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d
inna [77]

Answer:

10 db

Explanation:

Detailed explanation and calculation is shown in the image below

6 0
3 years ago
At t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is 6.00 i + 4.00 j m/s2 . It moves at constan
Jet001 [13]

The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time t_1, the acceleration vector has direction \theta_1 such that

\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ

which indicates the particle is situated at a point on the lower left half of the circle, while at time t_2 the acceleration has direction \theta_2 such that

\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ

which indicates the particle lies on the upper left half of the circle.

Notice that \theta_1-\theta_2=90^\circ. That is, the measure of the major arc between the particle's positions at t_1 and t_2 is 270 degrees, which means that t_2-t_1 is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.

Recall that

\|\vec a_{\rm rad}\|=\dfrac{4\pi^2R}{T^2}

where R is the radius of the circle and T is the period. We have

t_2-t_1=(5.00-2.00)\,\mathrm s=3.00\,\mathrm s\implies T=\dfrac{3.00\,\rm s}{\frac34}=4.00\,\mathrm s

and the magnitude of the particle's acceleration toward the center of the circle is

\|\vec a_{\rm rad}\|=\sqrt{\left(6.00\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(4.00\dfrac{\rm m}{\mathrm s^2}\right)^2}=7.21\dfrac{\rm m}{\mathrm s^2}

So we find that the path has a radius R of

7.21\dfrac{\rm m}{\mathrm s^2}=\dfrac{4\pi^2R}{(4.00\,\mathrm s)^2}\implies\boxed{R=2.92\,\mathrm m}

8 0
3 years ago
You are traveling along a freeway at 65 mi/h. You suddenly skid to a stop because of congestion in traffic. Where is the energy
sergey [27]

The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

  • An important part in work on discs.
  • A part in non-conservative work due to friction.

Work is defined by the scalar product of force and displacement.

          W = F . d

Where the bold indicate vectors, W is work, F is force and d is displacement.

The work energy theorem relates work and kinetic energy.

            W = ΔK = K_f - K_o

In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:  

          W = - K₀

Therefore, the initial kinetic energy that the car has is converted into work in its brakes.  In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.

In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

  • An important part in work on the discs.
  • A part in non-conservative work due to friction.

Learn more here:  brainly.com/question/17056946

8 0
3 years ago
Does the resistance of an object depend on the path current takes through it? Consider, for example, a rectangular bar—is its re
SVETLANKA909090 [29]

Answer:

Explanation:

An object's resistance depends on its form and the substance it is made from.  The electrical resistance R of the cylinder, as you might expect, is directly proportional to its length L, similar to a pipe's resistance to fluid flow. The longer the cylinder, the more charges of collisions with its atoms can occur. The bigger the cylinder diameter, the more current it can carry.

8 0
4 years ago
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