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3 years ago

Jade uses 8

Mathematics

1 answer:

DochEvi [55]3 years ago

7 0

Answer:

Step-by-step explanation:

if we divided 24/8 we can see that i takes 1 cup of flower for every 3 muffins so what divided by 3 gives us 30? 10 so you would need 10 cups

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A soda manufacturer knows that sales of soda increase during the summer. To make sure that they get a large portion of the sales

Alexxx [7]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: Number of winning caps out of 5 bottles.

Checking the binomial criteria:

- Number of trials is fixed n=5 bottles of soda

- Only two possible outcomes per trial: "success": winning cap; "failure": regular cap.

- The trial are independent.

- The probability of success is constant trough the experiment p= 1/12= 0.083

This variable has a binomial distribution with parameters n= 5 and p= 0.083

You have to calculate the probability of getting 4 out of 5 winning caps

P(X=4)

Using the following formula:

$P(X=4)= \frac{n!}{(n-X)!X!} * (p)^{X} * (q)^{n-X}= \frac{5!}{1!4!} * (0.083)^{4} * (0.917)^{1}= 0.0002$

Or using the tables for accumulated probabilities:

P(X=4)= P(X≤4)-P(X≤3)= 0.9999 - 0.9997= 0.0002

5 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0

3 years ago

How do you solve (4x)2/3

pishuonlain [190]

3.1 Solve : 4x2+3 = 0. Subtract 3 from both sides of the equation : 4x2 = -3. Divide both sides of the equation by 4: x2 = -3/4 = -0.750. When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get: x = ± √ -3/4. In Math, i is called the imaginary unit. It satisfies i 2 =-1.

4 0

3 years ago

A vertical pole is supported by two ropes staked to the ground on opposite sides of the pole. One rope is 8 meters long, and the

aniked [119]

Establish two right triangles, both with the height of the pole, h.

Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.

Apply Pytagora's equation to both triangles.

1) h^2 = 7^2 - x^2

2) h^2 = 8^2 - (6-x)^2

Eaual 1 to 2

7^2 - x^2 = 8^2 - 6^2 +12x -x^2

12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21

x = 1.75

Substitue x-value in 1

h^2 = 49 - (1.75)^2 = 45.94

h = sqrt(45.94) = 6.78

Answer: option d.

8 0

3 years ago

Read 2 more answers

What is the d/dx tan^3x

Bad White [126]

$\frac{d}{dx}(tan^{3}x) = \frac{d}{dx}(tanx)^{3}$
$= 3(tanx)^{2} \cdot sec^{2}x$

$\therefore \frac{d}{dx}(tan^{3}x) = 3tan^{2}x \cdot sec^{2}x$

6 0

4 years ago