Answer:
<h2>5</h2>
<em>Solution,</em>
<em>For </em><em>kite </em><em>adjacent,</em>
<em>Sides </em><em>are </em><em>equal</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
#4
White block(s) = 2
Red block(s) = 1
Purple block(s) = 3
Total = 2 +1 + 3 = 6 blocks
a) P(white) =

P(red) =

P(purple) =

b)Not white block:
1 -

OR

Because, when they say no white blocks, we simply do not count them and add the rest to find that probability without white blocks.
c) The probability stays the same: lets say now we have
4 white blocks, 2 red, and 6 purple, total will be 12
P(white)=

which is still

d) We get two more blocks in the numerator: lets say we have 4 white blocks, 3 red, 5 purple (after adding 2 of each color), total will be 12
P(purple)=

(im not quite sure if my explanation here helps you though)
e) 1 more of white and purple, 5 more of red
white = 3, purple = 4, red = 6, total = 12
(you can either add 2 to white or purple but make sure you add 5 of red)
P(red)=

=
Answer:
(7, -6)
Step-by-step explanation:
You want to find point X on the segment from A to B such that ...
(X -A)/(B -X) = 3/2
2(X -A) = 3(B -X) . . . . . . cross multiply
2X -2A = 3B -3X . . . . . eliminate parentheses
5X = 2A +3B . . . . . . . . add 3X +2A
X = (2A +3B)/5 . . . . . . . divide by 5
Filling in the given points for A and B, we have ...
X = (2(4, -3) +3(9, -8))/5 = (8+27, -6-24)/5 = (35, -30)/5
X = (7, -6)
The point that divides the segment in the proportions 3:2 is (7, -6).
I believe C because 1840+14%x2which would be the two years = 2355.20
I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)