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Olin [163]
3 years ago
10

A point on the rim of a wheel has a linear speed of 33 cm/s. If the radius of the wheel is 50 cm, what is the angular speed of t

he wheel in radians per second?
Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer:

The angular speed of the wheel in radians per second is 0.66.

Step-by-step explanation:

Recall the following statement:

A linear speed (v) is given by,  

v=\omega \times r                       ...... (1)

Here,  \omega represents the angular speed of the wheel and <em>r</em> represents the  radius of the wheel.

From the given information:

Linear speed (v) = 33 cm/s

Radius of the wheel (r) = 50 cm

Now to find the angular speed in radian per second.

33 =50 \times \omega

Divide both sides by 50.

0.66 rad/sec= \omega

Hence, the angular speed of the wheel in radians per second is 0.66.

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Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

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Number of students who plays base both the games = 8

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Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

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P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

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P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

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