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qwelly [4]
3 years ago
15

Look at the sets below.

Mathematics
1 answer:
ahrayia [7]3 years ago
6 0

Answer:

Answer is A

A contains all the elememts common to both the sets and thus it is the inteesection of the given two sets.

I hope this helps you

#Indian : )

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PLEASE HELP MEE!!b<br><br><br><br>znzjz<br><br><br><br><br><br><br><br>​
Bumek [7]

Answer:

∠A ≅ ∠E

∠B ≅ ∠F

∠C ≅ ∠G

AB ≅ EF

BC ≅ FG

CA ≅ GE

6 0
2 years ago
I need help on this question, not to good with graph. Anybody help pleaseee!!
LenKa [72]

y = -3x - 2

Since a < 0 we have a decreasing line, so it can be only the first or the last

And if we solve the equation for y = 0 we have

0 = -3x - 2

3x = -2

x = -2/3

So, the last one is the right

3 0
2 years ago
Brainliest fir CORRECT answer ​
viktelen [127]

Answer:

y ≈ 5.2

Step-by-step explanation:

∠ F = 180° - (42 + 48)° ← sum of angles in a triangle

∠ F = 180° - 90° = 90°

Thus Δ DEF is right at F

Using the sine ratio in the right triangle

sin48° = \frac{opposite}{hypotenuse} = \frac{DF}{DE} = \frac{y}{7} ( multiply both sides by 7 )

7 × sin48° = y , then

y ≈ 5.2 ( to the nearest tenth )

4 0
2 years ago
Tom was driving 20.3 meters per second in a 45 mile per hour zone. Was Tom speeding? Explain using a unit conversion as well as
My name is Ann [436]

Answer:

Tom was speeding.

Step-by-step explanation:

The driving speed of Tom = 20.3 meters per second.

Speed allowed in the zone = 45 miles per hour zone.

Since the unit of speed allowed is given in miles per hour but the speed of tom is given in meters per second. So, first, we have to convert the meter per second into mile per hour then we can compare and find that Tom is speeding or not.  

1 mile = 1609.34 meters

1 hour = 3600 second

Now convert 20.3 into mile per hour.

20.3 meters per second. = (20.3 / 1609.34)*3600 = 45.40981 mile per hour.

Since Tom’s speed is more than the allowed speed so he is speeding.

7 0
2 years ago
What is the Pythagorean Theorem
Vlad [161]

Answer:

see below

Step-by-step explanation:

The Pythagorean theorem is for right triangles.  It uses the two legs and the hypotenuse

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

4 0
2 years ago
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