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tino4ka555 [31]
3 years ago
10

Harry paid $35 for a tie and $11 for a T-shirt. He gave the cashier a 100-dollar bill. How much change did he receive from the c

ashier?
helpp​
Mathematics
2 answers:
MrMuchimi3 years ago
5 0

Answer:

The answer is $54

Step-by-step explanation:

Since Harry paid $35 for a tie and $11 for a T-shirt,he paid $46, if he gave the cashier $100, then he would get $56 back.

Step 1: Add how much he paid for the tie and T-shirt

$35 + $11 = $46

Step 2:Subtract 100 from the sum of the tie and T-shirt

$100 - $46 = $54

Step 3:Check the solution to make sure it's right

If 100 - 46 = 54, then 54 + 46 = 100

If 35 + 11 = 46, then 46 - 35 = 11

Correct Answer: $54

Vaselesa [24]3 years ago
4 0

Answer:

54

Step-by-step explanation: you add 35 and 11 together then subtract 100 by the number you got to get the anwser

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Just read explanation

Step-by-step explanation:

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Step-by-step explanation:

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x + 56 = 90

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The product of two rational numbers is 6 If one of them is 8 find the other numbers
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Step-by-step explanation:

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2 years ago
Evaluate each function following the specification.
telo118 [61]

Answer:

#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

\#4 \  a. \ h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

b. Yes, <em>x ≠ 2</em>

Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

g(0) = 3

g(1) = -1² + 3 = -1 + 3 = 2

g(1) = 2

g(-1) = 2, g(0) = 3, and g(1) = 2

b. The given function g(x) = -x² + 3 for finding the value of <em>g</em> can take any value of <em>x</em> which is a real number

Therefore, therefore, there are no restrictions

#4 a. The given function is given as follows;

h(x) = \dfrac{x}{x - 2}

By substitution, we get;

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\therefore h(-1) = \dfrac{1}{3}

h(0) = \dfrac{0}{0 - 2} = \dfrac{0}{-2} =0

\therefore h(0) =0

h(2) = \dfrac{2}{2 - 2} = \dfrac{2}{0} = \infty

\therefore h(2) =  \infty

h(-1) = \dfrac{1}{3}, \  h(0) =0, \  h(2) =  \infty

b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for <em>x</em> in the function, which is <em>x ≠ 2</em>

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