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Delicious77 [7]
4 years ago
5

g Suppose that twenty different hypothesis tests for whether jellybeans cause acne are conducted. In order that the probability

of one or more type I error between these should be at most 0.05, at most what significance level should be used for each of them?
Mathematics
1 answer:
Law Incorporation [45]4 years ago
6 0

Answer:

The level of significance to be used is α = 0.0025

Step-by-step explanation:

Here, we are interested in calculating the the level of significance which at most must be used for each of the hypothesis test

We proceed as follows;

P(type 1 error) = α

From the question, n = number of hypotheses = 20

P( of one or more type one error) ≤ 0.05

1- P(no type one error) ≤ 0.05

Hence;

1- (1-α)^20 ≤ 0.05

(1-α)^20 ≥ 0.95

1- α ≥ 0.997438621223

α ≤ 0.00256

Thus α = 0.0025

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Step-by-step explanation:

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6 0
4 years ago
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How many different triangles, if any, can be drawn with side lengths of 2 cm, 4 cm, and 7 cm?
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5 0
3 years ago
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Solve for m<br><img src="https://tex.z-dn.net/?f=g%20%3D%204cm%20-%203m" id="TexFormula1" title="g = 4cm - 3m" alt="g = 4cm - 3m
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This is what is called a literal equation.  Solve it for m just like you would solve any equation for x.  Isolate the term with the variable you're looking for.  Do this by subtracting 4cm from both sides to give you g - 4cm = -3m.  Now we need to divide by -3 to get m alone: \frac{g-4cm}{-3}=m.  Or we could lose the negative on the 3 in the denominator like this: \frac{-g+4cm}{3}=m and \frac{4cm-g}{3}=m.  There you go!  Any one of those last three would work.  It just depends upon how your teacher wants you to express your answer.
7 0
3 years ago
A boot has been designed which can be immersed for 12 hours without leaking. Five hundred pairs of the boots are tested and the
Natali [406]

Answer:

0.0312

Step-by-step explanation:

Given :

Mean or average time, xbar = 12.25

Standard deviation, s = 3

Sample size, n = 500

The test statistic :

(x - xbar) ÷ (s/sqrt(n))

(12 - 12.25) ÷ 3/sqrt(500)

-0.25 ÷ 0.1341640

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The Pvalue :

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Hence, the Pvalue = 0.0312

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3 years ago
Does this graph represent a function?
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Yeas it does represent a function
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3 years ago
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