Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.
<u>Solution:</u>
Given that,
Total circulation of local newspaper in 2000 = 3250
Total circulation of local newspaper in 2001 = 3640
Total circulation of local newspaper in 2002 = 4100
<em><u>Finding percent of increase in the newspaper’s circulation from 2000 to 2001:</u></em>
<em><u>Finding percent of increase in the newspaper’s circulation from 2001 to 2002:</u></em>
As we can see 12% < 12.6%
So period of 2001 to 2002 has higher increase percentage.
The answer would be y<-4/3x+4 if it’s 4x+3y<12 if it’s 4x+3y=12 the answer would be y=-4/3x+4. I don’t know what your implying but &12 so if it didn’t help I’m sorry. If this helped please mark me branliest
Answer: 11.9%
Step-by-step explanation:
Given : On a stretch of Interstate-89, car speed is a normally distributed variable with mph and mph.
Let x be a random variable that represents the car speed.
Since ,
z-score corresponds x = 73 ,
Required probability :
[using z-value table.]
Hence, the approximate percentage of cars are traveling faster than you = 11.9%
Answer:
Answer is Option A
Step-by-step explanation:
the things people do for points smh :/
We know, 1 yard=3 feet.
1 feet =12 inches.
Therefore, 1 yard in inches is,
Hence, 3 yards in inches is.,
Therefore, 3 yards is greater than 107 inches.