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zlopas [31]
3 years ago
9

How many different triangles, if any, can be drawn with side lengths of 2 cm, 4 cm, and 7 cm?

Mathematics
2 answers:
sveticcg [70]3 years ago
5 0

Answer:                                                                                                                         None of them.

STatiana [176]3 years ago
4 0

Answer:

None.

Step-by-step explanation:

None, because in any triangle any side must be less than the sum of the other 2 sides.

Here one side length 7 is greater than 4 +2  so a triangle cannot be formed.

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Simplify the expression.<br> (the quantity x to the one-sixth power end quantity to the power of 3.)
Usimov [2.4K]

Answer:

\sqrt{x}

Step-by-step explanation:

If we have that worded expression, we can convert it into actual mathematical terms.

x to the one sixth power: x^{\frac{1}{6}}

That to the power of 3:

(x^{\frac{1}{6}})^3

Using exponent rules, since we have a power to a power, the powers multiply, so:

x^{\frac{1}{6}\cdot 3}\\\\x^{\frac{3}{6}}\\\\ x^{\frac{1}{2}}

If we have a number to a fraction power, the denominator becomes the “find the (denominator) root of x.

So:

x^{\frac{1}{2}} = \sqrt{x}

Hope this helped!

8 0
2 years ago
Read 2 more answers
I need help please :)
kumpel [21]
20² = (8 + 8)² + x²
x = 12
-
the missing side has a value of 12, found using pythagorean theorem
6 0
3 years ago
Use the FOIL method to find the product below.
Marina86 [1]
The answer is B. 35x2 + 34x + 8
8 0
3 years ago
Please help with these 3 questions
Sever21 [200]

Answer: x = 11

Step-by-step explanation:

2x+5 = 3x-6

2x-3x = -6-5

-x = -11

x = 11

Double-check:
11*2= 22                   11*3=33

22+5 = 27                33-6= 27

4 0
2 years ago
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0
3 years ago
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