f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
Answer:
1680 possible pizzas
Step-by-step explanation:
Pizza contains 2 different meat and 3 different vegetables.
If there are 5 meats and 8 vegetables, the customer can select any one of 3 types of crust.
Total number of ways to select meat = 5C2
nCr = n! /(n-r)! r!
5C2 = 5! / (5-2)!2!
= 5! / 3!2!
= 10
Total number of ways to select vegetables = 8C3
= 8!/(8-3)!3!
= 8! / 5!3!
= 56
Total number of pizza choice that can be made = 3 * 5C2 * 8C3
= 3*10*56
= 1680 possible pizza
Answer:
y=8.50x+0.25
Step-by-step explanation:
She/he starts off with 8.50 and throughout the week she can earn 0.25 per joke. We don't know how many times a joke is made so it would be an x.
