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kenny6666 [7]
3 years ago
8

Given a data​ set, how do you know whether to calculate sigma or​ s? Choose the correct answer below. A. If the given data set c

ontains a large number of​ entries, then s is calculated. If the data set contains a small number of​ entries, then sigma is calculated. B. When given a data​ set, one would have to determine if it represented the population or if it was a sample taken from the population. If the data are a​ population, then sigma is calculated. If the data are a​ sample, then s is calculated. C. When given a data​ set, one would have to determine if it represented the population or if it was a sample taken from the population. If the data are a​ population, then s is calculated. If the data are a​ sample, then sigma is calculated. D. If the given data set contains a large number of​ entries, then sigma is calculated. If the data set contains a small number of​ entries, then s is calculated.
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

B

Step-by-step explanation:

S is the sample standard deviation, it is calculated when the observations represent a sample of the population. sigma is the population standard deviation, it is calculated when de observations are the whole population.

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Answer:

x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

Step-by-step explanation:

simplify \frac{-3}{x-2} by putting the negative sign on the outside. \frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)

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