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3 years ago

ABCDEFGHI is a regular 9-sided polygon.

Mathematics

1 answer:

Igoryamba3 years ago

6 0

Answer:

angle BEF = 100 degrees

Step-by-step explanation:

For a regular 9-sided polygon (nonagon),

each exterior angle = 360/9=40 degrees

each interior angle = 180-40 = 140 degrees.

Referring to diagram, in the trapezoid (trapezium) BCDE, the base angles are 180-140 = 40 degrees.

Therefore angle DEB = 40 degrees

that leaves BEF = 140-40 = 100 degrees

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In a study, Phoenix Marketing International identified Bridgeport, Connecticut; San Jose, California; Washington, DC; and Lexing

kati45 [8]

Answer:

The estimate of the percentage of millionaires in each of these cities:

Bridgeport San Jose Washington Lexington Park

CT CA D.C. MD

Percentage of

Millionaires 9% 12% 9% 8.3%

Step-by-step explanation:

Data and Calculations: City

Bridgeport, San Jose, Washington, Lexington Park,

Millionaire CT CA D.C. MD

Yes 45 36 36 33

No 455 264 364 367

Sample 500 300 400 400

Percentage of

Millionaires 45/500 36/300 36/400 33/400

= 0.09 0.12 0.09 0.0825

= 9% 12% 9% 8.3%

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3 years ago

A minibus drives with a constant speed of 80 miles per hour. How far can it travel in 2 1/2 hours?

deff fn [24]

Answer:

200 Miles

Step-by-step explanation:

8 0

3 years ago

I need help on this 3,4,and 2 help me solve one please

Mrrafil [7]

3) 12 divided by 3= 4

4 x 2= 8

4 0

4 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

Five sandwich rings are each cut into four pieces you then cut each of the pieces into three servings how many servings do you h

anastassius [24]

You would have 48 servings

8 0

4 years ago