Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:
What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So
has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I think it helps you!!
Roger is 17 :) have a nice day :)
Answer:
4 sqrt(5)
-----------------
5
83 +12 sqrt(35)
Step-by-step explanation:
1. 4 sqrt(6)
--------------------
sqrt(30)
Multiply the top and bottom by sqrt(30) to rationalize the denominator
4 sqrt(6) *sqrt(30)
--------------------
sqrt(30)*sqrt(30)
4 sqrt(180)
--------------------
30
Simplify
2 sqrt(36 *5)
--------------------
15
We know that sqrt(ab) = sqrt(a) sqrt(b)
2 sqrt(36)sqrt(5)
--------------------------
15
2 *6*sqrt(5)
-------------------
15
Simplify
2 * 2 sqrt(5)
---------------------
5
4 sqrt(5)
-----------------
5
2. (2 sqrt(5) + 3 sqrt(7))^2
(2 sqrt(5) + 3 sqrt(7)) (2 sqrt(5) + 3 sqrt(7))
FOIL
first 2sqrt(5)*2sqrt(5)=4*5=20
outer 2 sqrt(5) * 3 sqrt(7) = 6 sqrt(35)
inner 3 sqrt(7) *2 sqrt(5) = 6 sqrt(35)
last 3sqrt(7) 3sqrt(7) = 9*7 = 63
Add them together = 20 + 6 sqrt(35)+ 6 sqrt(35) +63 = 83 +12 sqrt(35)
Answer:
Step-by-step explanation:
We are basically trying to find the hypotenuse of the triangle.
The distance between the x is 2, and the distance between the y is 5, which makes a length and a width.
Pythagrenum theorem: a^2+b^2=c^2
2^2 is 4, 5^2 is 25.
4+25 is 29.
The distance is .
