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Monica [59]
3 years ago
6

The point (3, 6) is on the graph of y= 5f(2(x+3))-4 . Find the original point on the graph of y=f(x).

Mathematics
1 answer:
Sonja [21]3 years ago
7 0

Answer:

<em>(12, 2)</em> is the original point on the graph of y=f(x).

Step-by-step explanation:

<u>Given:</u>

y= 5f(2(x+3))-4 has a point <em>(3, 6)</em> on its graph.

<u>To find:</u>

Original point on graph y=f(x) = ?.

<u>Solution:</u>

We are given that The point (3, 6) is on the graph of y= 5f(2(x+3))-4

If we put x = 3 and y = 6 in y= 5f(2(x+3))-4, it will satisfy the equation.

Let us the put the values and observe:

6= 5f(2(3+3))-4\\\Rightarrow 6= 5f(2(6))-4\\\Rightarrow 6= 5f(12)-4\\\Rightarrow 6+4=5f(12)\\\Rightarrow 5f(12)= 6+4\\\Rightarrow 5f(12)= 10\\\Rightarrow f(12)= \dfrac{10}{5}\\\Rightarrow f(12)= 2\\OR\\\Rightarrow 2=f(12)

Now, let us compare the above with the following:

y=f(x)

we get y = 2 and x = 12

So, the original point on graph of y=f(x) is <em>(12, 2).</em>

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