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zysi [14]
3 years ago
15

3^4x+^2=9^x+^2. what is the value of x?​

Mathematics
1 answer:
klemol [59]3 years ago
5 0

Answer:

x = 1

Step-by-step explanation:

3^(4x + 2) = 9^(x + 2)

Make 9 with base 3.

3^(4x + 2) = (3^2)^(x + 2)

3^(4x + 2) = 3^(2x + 4)

Cancel bases.

4x + 2 = 2x + 4

Subtract 2 and 2x on both sides.

4x - 2x = 4 - 2

2x = 2

Divide 2 on both sides.

x = 1

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ankoles [38]

Answer:

The answer is 135 degrees.

Step-by-step explanation:

As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.

r(t)=(2t)i+(2t-16t^{2})j

V(t)=2i+(2-32t)j

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v(t)=2i+2j

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As i attach in the picture the angle between the velocity and acceleration vector is (45+90)=135 degrees

4 0
3 years ago
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A. 8 HOPE THIS IS CORRECT!
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3 years ago
Simplify: 4.16-1.1*2.6+0.7 squared
ser-zykov [4K]

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1.79

Step-by-step explanation:

the way you wrote the question is questionable

4 0
3 years ago
HELP PLEASE!
Doss [256]
D.
first, eliminate B and C, because the highest degree in these two equation is 3, a 3-degree equation has 3 roots, not 4. 

between A and D, A has the roots 0, 0, 7, and -7, all real roots.

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2 years ago
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