A candy store sells 8 pound bags of mixed almonds and cashews. If c pounds of cashews are in a bag,...
c=1 was already given as described. The store sells pound bags.
The rest of the description and question seem not to match. Maybe each bag contains 8 pounds of the two nuts. Eight pounds and some of this is of cashews. Now, c is how many pounds of cashews in one bag.
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p=2.59%2Ac%2B1.72%288-c%29
You want to know the quantity of cashews if p=18.11 dollars per bag.
2.59c%2B1.72%2A8-1.72c=p
2.59c-1.72c=p-1.72%2A8
%282.59-1.72%29c=p-1.72%2A8
0.87c=p-13.76
Answer:
14.656%
Step-by-step explanation:
Data provided in the question:
Rate of return, r = 4% = 0.04
Risk aversion of A = 1.85
Standard deviation, σ = 24%
Now,
we have the relation
A = (E - r) ÷ σ²
E = expected return on portfolio
r = Risk free rate
on substituting the respective values, we get
1.85 = (E - 0.04) ÷ (0.24)²
or
0.0576 × 1.85 = (E - 0.04)
or
0.10656 + 0.04 = E
or
E = 0.14656 or
E = 0.14656 × 100% = 14.656%
As a fraction it would be 8/5
Answer: 2.25
Step-by-step explanation:
1 cm/ 2 in = x/ 4.5 in
2x = 4.5 in
4.5/2 = x
2.25 = x
Answer:
He saw <u>1 duck</u> and <u>3 dogs</u>.
Step-by-step explanation:
Given:
Evan went to the park and saw four animals.
Each animal was either a duck or a dog.
He saw a total of 14 legs.
Now, to find the number of each animal he had seen.
Let the number of duck be 
And the number of dog be 
So, total number of animals:
Now, the total number of legs he did see:
<em>As we know the legs of a duck are 2 and a dog are 4.</em>
Adding both sides by -16 we get:
Dividing both sides by -2 we get:
The number of duck = 1.
Now, putting the value of 
in above equation we get:
The number of dogs = 3.
Therefore, he saw 1 duck and 3 dogs.
