Consider the expression

Factorize the numerator and denominator a difference/sum of cubes:

Expand the denominator:

since <em>x</em> = 2020, and clearly 2020² + 2020 + 1 ≠ 0, so we can cancel the factor of <em>x</em> ² + <em>x</em> + 1. This leaves us with

so that <em>a</em> + <em>b</em> = 673 + 674 = 1347.
Get the greatest common factor.
11
divide both numbers by gcf
22/11=2
33/11=3
Answer: 2:3
<em>Hello!</em>
<u><em>Here are your answers:</em></u>
<em>-It is greater than 3</em>
<em>-It is between 3 and 4</em>
<em>This is based off of the options that were given.</em>
Answer is B. 4,096
I encountered this problem before. This is a trick question.
84 is not really the number 84. It is 8 raised to the 4th power.
So 8⁴ is equal to 4,096.
8 x 8 x 8 x 8 = 4,096
8 x 8 = 64
64 x 8 = 512
512 x 8 = 4,096