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3 years ago

Which set of ordered pairs represents y as a function of x?

Mathematics

1 answer:

givi [52]3 years ago

7 0

I think the answer is j

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Solve the system of equations and choose the correct answer from the list of options.

SpyIntel [72]

(3, -2) satisfies both equations. 3-2=1, and -3-2=-5.

7 0

3 years ago

Read 2 more answers

The value of x is approximately:

solong [7]

Answer:

19.80

Step-by-step explanation:

tan 22= 8/x

tan 22 = 8/x

x = 8/tan 22

x = 19.80

7 0

2 years ago

When multiplying exponential terms with the same base, which best explains how to simplify the expression?

ololo11 [35]

Answer:

First answer: "Add the exponents"

Step-by-step explanation:

The laws of exponents include the following for product of exponents with the same base:

$x^a\,*\,x^b = x^{a+b}$

which implies addition of exponents

So you need to add exponents

5 0

3 years ago

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago

An art supply store typically sells bottles of green paint for every 9 bottles of aqua paint. How many bottles of aqua paint doe

Feliz [49]

Need points sorry. Good luck tho

7 0

2 years ago