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2 years ago

I would like some help please.

Mathematics

1 answer:

DiKsa [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Because the other two are false.

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What is the surface area of the square pyramid?

Marrrta [24]

Answer:

Right square pyramid

Solve for surface area

A=a2+2aa2

4+h2

a Base edge

Enter value

h Height

5 0

2 years ago

A 91 square foot bathroom has a length of 13 feet. what is the width of the bathroom

Radda [10]

<span>The answer is 7 ft. The bathroom has rectangular shape. The area (A) of a rectangle is the product of the width (w) and length (l): A = w * h. The bathroom is rectangular. We know that A = 91 ft^2 and l = 13 ft. Let's substitute them in the formula for the area: 91 ft^2 = w * 13 ft. w = 91 ft^2 : 13 ft. w = 7 ft. The width of the bathroom is 7 ft.Hope this helps. Let me know if you need additional help!</span>

5 0

2 years ago

Read 2 more answers

What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b

kramer

Option C: $a=3, b=4$ is the value of a and b

Explanation:

Given that the expression $\sqrt{648}=\sqrt{2^a\times3^b}$

We need to determine the value of a and b

Let us consider the term $\sqrt{648}$ and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

$648=2 \cdot 324$

324 divides by 2,

$648=2 \cdot 2 \cdot 162$

162 divides by 2,

$648=2 \cdot 2 \cdot 2 \cdot 81$

81 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27$

27 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9$

9 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3$

Thus, we have,

$\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}$

Therefore, equating the powers of 2 and 3, we get,

$a=3, b=4$

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0

3 years ago

Read 2 more answers

Para decorar una pared se disponen de tiras de papel azules de 15 cm, verdes de 20 cm, y rojas de 25 cm. En la pared se quiere a

den301095 [7]

Answer:

a) Smallest line that can be made with each color = 300 cm

b) Total strips should be used = 47 strips

c) Total strips used of blue color = 20

Total strips used of green color = 15

Total strips used of red color = 12

Step-by-step explanation:

Given - To decorate a wall, there are 15 cm blue, 20 cm green, and 25 cm red strips of paper. On the wall you want to build three lines of the same size, one of each color and without cutting any strip.

To find - a) How long is the smallest line that can be made with each color?

b) How many strips should be used?

c) How many of each color?

Proof -

For the smallest line that can be made with each color, we just have to find the lcm (least common multiple) of the 3 srtips.

Firstly,

Decompose the 3 strips to its prime factors , we get

15 = 3×5

20 = 2²×5

25 = 5²

So,

The Lcm(15, 20, 25) = 3×2²×5² = 3×4×25 = 300

∴ we get

Smallest line that can be made with each color = 300 cm

Now,

Total strips used = 300 cm

Strips used by 15 cm blue = $\frac{300}{15}$ = 20 strips

Strips used by 20 cm green = $\frac{300}{20}$ = 15 strips

Strips used by 25 cm red = $\frac{300}{25}$ = 12 strips

So,

Total strips should be used = 20 + 15 + 12 = 47 strips

Total strips used of blue color = 20

Total strips used of green color = 15

Total strips used of red color = 12

6 0

2 years ago

Write a fraction greater than 1 for 6 using 9 as the denominator

svet-max [94.6K]

8/9. hope this helped

6 0

3 years ago