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jenyasd209 [6]
3 years ago
14

What is the quotient of the rational expression shown below? Make sure your answer is in reduced form x^2-4/x+3 divided x^2-4x+4

/4x+2
Mathematics
1 answer:
natita [175]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Given

\frac{x^2-4}{x+3} ÷ \frac{x^2-4x+4}{4x+2}

The first step is to factor numerators/denominators, if possible

x² - 4 = (x - 2)(x + 2) ← difference of squares

x² - 4x + 4 = (x - 2)(x - 2) ← perfect square

4x + 2 = 2(2x + 1)

To divide the expressions follow the steps

• Leave the first fraction

• Change division to multiplication

• Turn the second fraction upside down

We now have

\frac{(x-2)(x+2)}{x+3} × \frac{2(2x+1)}{(x-2)(x-2)}

Final step is to cancel common factors from the numerators/denominators

= \frac{2(2x+1)(x+2)}{(x+3)(x-2)} ← quotient


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2) we know that

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∡K=α

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KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

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