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hammer [34]
3 years ago
13

What is the circumference of a circle with a diameter of 5 feet? use 3.14 for pi

Mathematics
1 answer:
artcher [175]3 years ago
7 0

Answer:

15.7

Step-by-step explanation:

Circumference= πd

d= Diameter

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If q = 3, what is the value of the expression 7(2q − 5)? -28 7 21 37
alisha [4.7K]
7(2q-5)      {{q=3}}
= 7(2x3-5) 
= 7(6-5)
= 7(1)
= 7

The answer is 7. 

7 0
3 years ago
PLEASE HELP!!!<br> What is -5/8 times 2/3?
malfutka [58]

Simplify for -5/8*2/3= -5/12

-0.416 as a mixed number

6 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
WWhat is the value of p2+p+10 when p=4​
Reptile [31]

Answer:

value = 30(thirty).....

7 0
3 years ago
(1.7x10^13)+(0.8x10^13)
maks197457 [2]

Answer:

(1.7x10^13)+(0.8x10^13)

=(1.7x1e+13)+(0.8x1e+13)

=1.7e+13+0.8e+13

=2.5e+13

in actual number it would be 25,000,000,000,000

Step-by-step explanation:

3 0
2 years ago
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