All categories

2 years ago

Find the area and perimeter of this shape.

Mathematics

1 answer:

denpristay [2]2 years ago

4 0

Answer:

Step-by-step explanation:

since, it is a parallelogram we can find the area easily just by multiplying the base and height

A=bh

A=55m2

You might be interested in

If it takes 1 3/4 m of cloth to make a dress. How many dresses can be made from 10 1/2 m of cloth?

Amanda [17]

Answer:

Step-by-step explanation:

1¾ can go into 10½ 6 times

just divide them

7 0

3 years ago

What is the area of a regular octagon with a side length of 4.6 meters and a length from the center to a vertex of 6 meters? HEL

Shtirlitz [24]

What is the area of a regular octagon with a side length of 4.6 meters and a length from the center to a vertex of 6 meters?

Good Morning

The Correct Answer is c) 101.2

Hope I Helped

-Nullgaming650

6 0

3 years ago

What's the prime factor of 92 ?

mariarad [96]

Prime factors are multiplying numbers that cannot be divided into smaller numbers.
Let's break down 92.
Divide 92 by 2.
2 x 46.
We can still break this down.
Divide 46 by 2.
2 x 2 x 23.
This is your prime factorization of 92.
I hope this helps!

8 0

3 years ago

Read 2 more answers

Please help!!! Use the Pythagorean theorem to find the missing value

Alika [10]

Answer: 1. is 50 2. is 111 3. is 26 4. is 45 and 5. is 51

Step-by-step explanation: The formula for Pythagorean theorem is A^2 plus B^2 = c^2

Sry that took so long did it wrong at first

3 0

3 years ago

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

Zarrin [17]

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let X = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, λ = 11/ hour.

The random variable X follows a Poisson distribution with parameter λ = 11.

The probability mass function of X is:

$P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....$

It is provided that in t hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of t as follows:

$P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds$

Thus, the length of the interval during which no messages arrive is 90 seconds long.

6 0

4 years ago