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n200080 [17]
3 years ago
10

12)

Mathematics
1 answer:
kirill [66]3 years ago
7 0

Answer:

Project A : $58,000

Project B: $52800

Project A should be selected as it has a higher expected profit value than project B

Step-by-step explanation:

Given the following:

PROJECT A:

Profit : ---------50000--90,000--10,000

Probability: ----0.6-------0.3--------0.1

PROJECT B:

Loss of 20,000 = -20,000 in profit terms

Profit : -----100,000--64,000--(-20,000)

Probability: ----0.1-------0.7--------0.2

Expected profit:

Profit value * probability of profit

Expected profit on project A:

[(50000*0.6)+(90000*0.3)+(10000*0.1)

30000 + 27000 + 1000 = $58000

Expected profit on project B:

[(100000*0.1)+(64000*0.7)+(-20000*0.2)

10000 + 44800 - 4000 = $50800

Project A should be selected as it has a higher expected profit value than project B

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Given f(x) = (lnx)^3 find the line tangent to f at x = 3
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Explanation

We must the tangent line at x = 3 of the function:

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y=m*(x-h)+k.

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,

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In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

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y=(\ln3)^2*(x-3)+(\ln3)^3.

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Answer

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y=(\ln3)^2*(x-3)+(\ln3)^3

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Answer:

hello :  

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The interquartile range is 13.
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