Answer: Machine A makes popcorn at a rate of 4.25 ozs per minute (12.75oz/3min).
Machine B makes popcorn at a rate of 4.5 ozs per minute (18oz/4min).
Machine A will make 4.25oz/min * 10minutes = 42.5oz of popcorn after 10 minutes
Machine B will make 4.5oz/min * 10 minutes = 45oz of popcorn after 10 minutes
After 10 minutes there will be a total of 42.5oz (Machine A) +45oz (Machine B) = 87.5oz.
So the answer is: Yes there will be (more than) enough popcorn if both machines make popcorn for 10 minutes.
If the question is wondering how many 9oz bags they can fill: 87.5oz/9oz per bag = 9.7222 bags. The machines can fill 9, 9oz, bags with some popcorn leftover.
Step-by-step explanation:
Answer:
3 inches apart
Step-by-step explanation:
1/2 yard is 1ft. 6in. in decimal that is 1.5 ft
1.5 ÷6 = 0.25ft
0.25ft is 3 inches so the answer is three inches apart
Answer:
Step-by-step explanation:
subtract by 5 on both sides. ur left with
square root b and 16. the square root cancels out b squared. find the square root of 16. the square root of 16 is 4
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
