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vlada-n [284]
2 years ago
14

Q5. At a certain time of day, a man 6 feet tall casts a shadow 4 feet in length. At the

Mathematics
1 answer:
nirvana33 [79]2 years ago
8 0

The height of the church steeple is 42 feet

<h3>How to determine how high, in feet, is the church steeple?</h3>

The given parameters are

Height of the man = 6 feet

Length of the man's shadow = 4 feet

Length of the shadow of the church steeple = 28 feet

To determine how high, in feet, is the church steeple, we use the following equivalent ratio:

Height of the man : Length of the man's shadow = Height of the church steeple: Length of the shadow of the church steeple

Substitute the known values in the above equation

6 feet : 4 feet = Height of the church steeple : 28 feet

Express the above equation as a fraction

6 feet/4 feet = Height of the church steeple/28 feet

Multiply both sides of the above equation by 28 feet

28 feet * 6 feet/4 feet = Height of the church steeple/28 feet * 28 feet

This gives

28 feet * 6 feet/4 feet = Height of the church steeple

Evaluate the product in the above equation

168 feet/4 = Height of the church steeple

Evaluate the quotient in the above equation

42 feet = Height of the church steeple

Rewrite as:

Height of the church steeple = 42 feet

Hence, the height of the church steeple is 42 feet

Read more about equivalent ratios at:

brainly.com/question/2328454

#SPJ1

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3 years ago
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the half-life of uranium -238 is 4.5 × 10 to the power of 9 years. The half-life of uranium-238 than that of uranium-234
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Answer:

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Step-by-step explanation:


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