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Julli [10]
3 years ago
12

Does anyone know this i need an answer asap btw its 8th grade work

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0
Quadrilateral 2 will be parallel just like the first Quadrilateral. The shapes are the same and AD and BC are parallel on both shapes.
You might be interested in
Find the gcf of 12 and 45
krek1111 [17]

gcf = 3

the factors of 12 are 1, 2, 3, 4, 6 and 12

the factors of 45 are 1, 3, 5, 9, 15 and 45

the greatest common factor of 12 and 45 is 3


3 0
3 years ago
Read 2 more answers
You have a carton of 48 Easter eggs left from the weekend. You check the weight of the
crimeas [40]

Answer:

around 6 and a half pounds

4 0
2 years ago
Solve |2x|=8<br> Tell me how you got the answer pls
lilavasa [31]

Answer:

4

Step-by-step explanation:

2 x 4 = 8

Absolute value means no symbols so it would just be 2 x something equals 8 which is 4.

6 0
3 years ago
Work out the value of: 5x - 2y when x = 3 and y = 4
KATRIN_1 [288]
The expression is 5x - 2y
Use PEMDAS and work out the rest
x = 3 and y = 4
5 x = 5 x 3 = 15
2 y = 2 x 4 = 8
15( x ) - 8 (y) = 7
The answer is 7

Hope This Helps You!
Good Luck Studying :)
4 0
3 years ago
Read 2 more answers
given sin A =3/-/34 and that angle S is in quadrant 1, find the exact value of tan A in simplest radical form using a ration
Vedmedyk [2.9K]

Answer:

\tan(A) = \frac{3}{5}

Step-by-step explanation:

Given

\sin(A) = \frac{3}{\sqrt {34}}

0 \le A \le 90 --- First Quadrant

Required

Find tan(A)

The sin of an angle is:

\tan(A) = \frac{Opposite}{Hypotenuse}

and

\sin(A) = \frac{3}{\sqrt {34}}

By comparison:

Opposite = 3

Hypotenuse = \sqrt{34

So, the Adjacent is:

Hypotenuse^2 = Adjacent^2 + Opposite^2

(\sqrt{34})^2 = Adjacent^2 + 3^2

34 = Adjacent^2 + 9

Collect like terms

Adjacent^2 =34 - 9

Adjacent^2 =25

Take square roots

Adjacent =\sqrt{25

Adjacent =5

The tangent of an angle is:

\tan(A) = \frac{Opposite}{Adjacent}

This gives:

\tan(A) = \frac{3}{5}

8 0
3 years ago
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