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Studentka2010 [4]
3 years ago
12

Athena was completing a puzzle picture by connecting ordered pairs of points. Her next point is described below:

Mathematics
2 answers:
Viefleur [7K]3 years ago
5 0

Answer:

I'm not sure but maybe (-1, 2)

nydimaria [60]3 years ago
4 0
Corvette corvette hop in the jet
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A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh
Stella [2.4K]

A parabola is a mirror-symmetrical U-shape.

  • The equation of the parabola is \mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}
  • The focus is \mathbf{Focus = (80, -1760)}
  • The directrix is \mathbf{y = \frac{1}{640}}
  • The axis of the symmetry of parabola is: \mathbf{x = 80}

From the question, we have:

\mathbf{Vertex: (h,k) = (80,10)}

\mathbf{Origin: (x,y) = (0,0)}

The equation of a parabola is:

\mathbf{y = a(x - h)^2 + k}

Substitute the values of origin and vertex in \mathbf{y = a(x - h)^2 + k}

\mathbf{0 = a(0 - 80)^2 + 10}

\mathbf{0 = a(- 80)^2 + 10}

\mathbf{0 = 6400a + 10}

Collect like terms

\mathbf{6400a =- 10}

Solve for a

\mathbf{a =- \frac{1}{640}}

Substitute the values of a and the vertex in \mathbf{y = a(x - h)^2 + k}

\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}

The focus of a parabola is:

\mathbf{Focus = (h, \frac{k+1}{4a})}

Substitute the values of a and the vertex in \mathbf{Focus = (h, \frac{k+1}{4a})}

\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}

\mathbf{Focus = (80, -\frac{11}{\frac{1}{160}})}

\mathbf{Focus = (80, -11\times 160)}

\mathbf{Focus = (80, -1760)}

The equation of the directrix is:

\mathbf{y = -a}

So, we have:

\mathbf{y = \frac{1}{640}} ----- the directrix

The axis of symmetry is:

\mathbf{x = -\frac{b}{2a}}

We have:

\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}

Expand

\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}

Expand

\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}

\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }

A quadratic function is represented as:

\mathbf{y = ax^2 + bx + c}

So, we have:

\mathbf{a = -\frac{1}{640}}

\mathbf{b = \frac{1}{4}}

Recall that:

\mathbf{x = -\frac{b}{2a}}

So, we have:

\mathbf{x = -\frac{1/4}{2 \times -1/640}}

\mathbf{x = \frac{1/4}{1/320}}

This gives

\mathbf{x = \frac{320}{4}}

\mathbf{x = 80}

Hence, the axis of the symmetry of parabola is: \mathbf{x = 80}

Read more about parabola at:

brainly.com/question/21685473

6 0
3 years ago
The point (3,-7) lies on a circle and the center of the circle is at (-2,-7). What is the equation of this circle
melomori [17]

Step-by-step explanation:

the answer is in the above image

4 0
3 years ago
Please help me I need assistance
lawyer [7]

(\stackrel{x_1}{2}~,~\stackrel{y_1}{-15})\qquad (\stackrel{x_2}{14}~,~\stackrel{y_2}{r}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{r}-\stackrel{y1}{(-15)}}}{\underset{run} {\underset{x_2}{14}-\underset{x_1}{2}}}~~ = ~~\stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{4}}\implies \cfrac{r+15}{12}~~ = ~~\cfrac{3}{4}\implies r+15 = \cfrac{12\cdot 3}{4} \\\\\\ r+15=9\implies \boxed{r=-6}

3 0
2 years ago
Pls help me answer this :'(
anzhelika [568]

Answer:

I believe the answer is D :)

4 0
3 years ago
On January 16 the temperature in Boston was -8 degrees at 4:00am and it when began to rise 3degrees every hours. What was the te
ANTONII [103]

Answer:

22 degrees

Step-by-step explanation:

6 0
3 years ago
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