Mean:
E[Y] = E[3X₁ + X₂]
E[Y] = 3 E[X₁] + E[X₂]
E[Y] = 3µ + µ
E[Y] = 4µ
Variance:
Var[Y] = Var[3X₁ + X₂]
Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]
(the covariance is 0 since X₁ and X₂ are independent)
Var[Y] = 9 Var[X₁] + Var[X₂]
Var[Y] = 9σ² + σ²
Var[Y] = 10σ²
4x^2 - 64
= 4(x + 4) (x - 4)
You mix the letters m,a,t,h,e,m,a,t,i,c,a and l thoroughly without looking you draw one letter probability p(A) . write the prob
erastovalidia [21]
There are 12 total letters, of which 3 are A's.
This means you have a
probability of randomly selecting an A.
Answer:
150(1-x)
Step-by-step explanation:
120 is decreased by d%
Let x = d%
120 - 120*x
120(1-x)
Then it is increased by 25%
(120 (1-x)) +(120 (1-x))*.25
(120 (1-x)) +(30 (1-x))
150(1-x)
Answer:
The ASAP Math program provides an opportunity for additional small group instruction for students who find the math program challenging. Students in grades 1 to 4 will come to the ASAP room two to three times a week during the math block.
Step-by-step explanation:
