All categories

2 years ago

Please help what is the answer?

Mathematics

1 answer:

mojhsa [17]2 years ago

8 0

The answer would be C

You might be interested in

The ratio of the heights of two similar cylinders is 1:3. If the volume of the smaller cylinder is 67 cubic cm, find the volume

Andreyy89

The volume is 18.72

8 0

2 years ago

(-4x-2)+1/2(12x-22) simplify

Ierofanga [76]

Answer:

2x - 13

Step-by-step explanation:

Step 1 :

Simplify —

Equation at the end of step 1 :

(-4x - 2) + (— • (12x - 22))

Step 2 : Pulling out like terms :

3.1 Pull out like factors :

12x - 22 = 2 • (6x - 11)

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

12x - 22 = 2 • (6x - 11)

Equation at the end of step 3 :

(-4x - 2) + (6x - 11)

6 0

2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

2 years ago

Math help please I need it ASAP

statuscvo [17]

Answer:

x=10.5

Step-by-step explanation:

$\frac{x}{6} =\frac{7}{4} \\x=\frac{7}{4} \times 6\\=\frac{21}{2} \\=10.5$

4 0

2 years ago

A rectangular yard is 18 feet long. The area if the yard is 400.5 square ft. What is the width of the yard?

WARRIOR [948]

Answer:

22.25 feet wide

Step-by-step explanation:

A = lw

400.5 = 18x

Divide 18 on both sides

22.25 = x

4 0

3 years ago