3 years ago

Describe and correct the error in telling whether the two figures are congruent?

Mathematics

2 answers:

Aleks04 [339]3 years ago

4 0

2 figures are congruent if at least 2 sides are the same length, there angles are the same, etc

romanna [79]3 years ago

3 0

When figures are CONGRUENT, they have the SAME SIZE, SIDE LENGTHS OR WIDTH, And ANGLES

You might be interested in

Man can so help me wit this ixk and give the real answer ill give u 80 point plz

Artemon [7]

Answer:

136

Step-by-step explanation:

7 0

3 years ago

Write 63000 in standard form

WINSTONCH [101]

63000 is already in standard form

7 0

3 years ago

Read 2 more answers

Can you help me please!!

laiz [17]

Answer:

Step-by-step explanation:

To find them you need to plug them in to solve and then eliminate the following by the pass through method. This can help bring the final answer to the "table" leaving you with the final measure of each described angle.

6 0

3 years ago

3(2x + 12) = -2(x - 4) + x

mart [117]

Answer:

-4

Step-by-step explanation:

1. Use the distributive property to get 6x + 36 = -2x + 8 + x

2. Combine like terms 6x + 36 = -x + 8

3. Subtract 36 on both sides. 7x + 36 = 8 > 7x = -28

4. Divide by 7

-28/7 = -4 x=4

5 0

4 years ago

Read 2 more answers

(a^2-ax+bx-ab)/(a^2+ax-bx-ab)*(a^2+ax+ab+bx)/(a^2-ax-ab+bx)

Vanyuwa [196]

$\frac{a^2-ax+bx-ab}{a^2+ax-bx-ab} \cdot \frac{a^2+ax+ab+bx}{a^2-ax-ab+bx} = \frac{1}{a(a+x)-b(x+a)} \cdot (a(a+x)+b(a+x)) = \frac{1}{a-b} \cdot (a+b) = \frac{a+b}{a-b}.$

8 0

3 years ago