Answer:
the answer is m = 2
Step-by-step explanation:
Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.
hope this helps
Answer:
y - 1 = 2(x - 2)
General Formulas and Concepts:
<u>Algebra I</u>
Point-Slope Form: y - y₁ = m(x - x₁)
- x₁ - x coordinate
- y₁ - y coordinate
- m - slope
Step-by-step explanation:
<u>Step 1: Define</u>
Slope <em>m</em> = 2
Point (2, 1)
<u>Step 2: Write Equation</u>
- Substitute in variables: y - 1 = 2(x - 2)
Below are the choices:
A. 80 mL of the 3.5% solution and 120 mL of the 6% solution
<span>B. 120 mL of the 3.5% solution and 80 mL of the 6% solution </span>
<span>C. 140 mL of the 3.5% solution and 60 mL of the 6% solution </span>
<span>D. 120 mL of the 3.5% solution and 80 mL of the 6% solution
</span>
Let fraction of 3.5% in final solution be p.
<span>p * 3.5 + (1 - p) * 6 = 4.5 </span>
<span>3.5p + 6 - 6p = 4.5 </span>
<span>2.5p = 1.5 </span>
<span>p = 3/5 </span>
<span>3/5 * 200 = 120 </span>
<span>Therefore the answer is B. 120 ml of 3.5% and 80 ml of 6%.</span>
Answer:

(You only need to give one solution)
Step-by-step explanation:
We have the following equation

First, we need to foil out the parenthesis

Now we can combine the like terms

Now, we need to factor this equation.
To factor this, we need to find a set of numbers that add together to get -3 and multiply to give us -4.
The pair of numbers that would do this would be 1 and -4.
This means that our factored form would be

As the first binomial is a difference of squares, it can be factored futher into

Now, we can get our solutions.
The first binomial will produce two complex (Not real) solutions.


So our solutions to this equation are

If B is the midpoint of AC, then AB = BC.
We have AB = x + 5 and BC = 2x - 11.
Therefore we have the equation:
x + 5 = 2x - 11 <em>subtract 5 from both sides</em>
x = 2x - 16 <em>subtract 2x from both sides</em>
-x = -16 <em>change the signs</em>
x = 16
Put the value of x to the expression x + 5:
AB = 16 + 5 = 21
<h3>Answer: AB = 21</h3>