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-BARSIC- [3]
2 years ago
15

On a coordinate plane, a line goes through points (0, 1) and (3, 0). Y = one-half x minus 1.

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
7 0

Answer:

Step-by-step explanation:

1. -1/2

2. -1

3. -1/2

4. -1

crimeas [40]2 years ago
6 0

Answer:

Identify the slope of the graphed line:   -1/3

Identify the y-intercept of the graphed line:   1

Identify the slope of the line given by the equation:   1/2

Identify the y-intercept of the line given by the equation:  -1

Step-by-step explanation:

the other person is wrong i got a 100 on my assignment its correct on edge 2021 hope this helps!!

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I need help with this problem
marishachu [46]

True

∠2 and ∠5 are both vertical at the vertex of the 2 straight lines



7 0
3 years ago
This is pre calculus please help !Describe three ways to determine the measure of segment YZ.
Dmitry [639]
(1) Using trigonometric ratios:
sin(30) = \frac{YZ}{50}
YZ = 25

(2) Using Pythagoras' Theorem:
cos(30) = \frac{XY}{50}
50cos(30) = XY
50^{2} - 50^{2}cos^{2}(30) = YZ^{2}
2500 - 2500cos^{2}(30) = YZ^{2}
YZ = 25

(3) Using sine rule:
\frac{50}{sin(90)} = \frac{YZ}{sin(30)}
50 = \frac{YZ}{sin(30)}
50sin(30) = YZ
YZ = 25
7 0
3 years ago
Read 2 more answers
Factor the following question x^{2} -9x-36
Klio2033 [76]

Step-by-step explanation:

{x}^{2}  - 9x - 36 \\ (x - 12)(x + 3)

3 0
3 years ago
How is 0.9999 Equal to 1 again?
DochEvi [55]
It’s not exactly equal to one, but in many cases in math they ask for a rounded answer.
3 0
3 years ago
An equilateral triangle has a perimeter of 48 cm. What is the area?
KiRa [710]

Answer:

A=64\sqrt{3}\ cm^2

Step-by-step explanation:

we know that

An <u><em>equilateral triangle</em></u> has three equal sides and three equal interior angles (each interior angle measure 60 degrees)

so

The perimeter is equal to

P=3b

where

b is the length side of the equilateral triangle

we have

P=48\ cm

substitute

48=3b

solve for b

b=48/3\\b=16\ cm

Find the area

The formula of area applying the law of sines is equal to

A=\frac{1}{2}b^2sin(60^o)

substitute the value of b

A=\frac{1}{2}(16)^2sin(60^o)

sin(60^o)=\frac{\sqrt{3}}{2}

A=\frac{1}{2}(16)^2(\frac{\sqrt{3}}{2})

A=64\sqrt{3}\ cm^2

6 0
3 years ago
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