Answer:
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Answer: 26 pieces of $1 bill and 34 pieces of $5 bill
Total Deposit = $196
Total Bills = 60 pieces
Value of $1 = $1
Value of $5 = $5
Lets assume all the 60 pieces were $1 bill.
The total deposit will be 60 x $1 = $60
But we know that the total deposit is $196. So the extra value must have come from the $5.
$196 - $60 = $136
There is still an outstanding amount of $136 not accounted for.
$5 - $1 = $4
The difference in the two bills is $4
Now we can find out the number of $5 bill by dividing the extra $136 by 4:
136 ÷ 4 = 34 pieces
There are 34 pieces of $5 bill.
Since there are 34 pieces of $5, the rest must be the $1 bill
60 - 34 = 26
There are 26 pieces of $1 bill.
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Answer: 26 pieces of $1 bill and 34 pieces of $5 bill.
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If 
is a zero of 
, then we can write
for another polynomial 
.
Note that 
. Then
so that 
is a root of 
.
Answer:
w = -4
Step-by-step explanation:
Solve for w:
17 - 3 (w + 5) = 6 (w + 5) - 2 w
-3 (w + 5) = -3 w - 15:
-3 w - 15 + 17 = 6 (w + 5) - 2 w
Grouping like terms, -3 w - 15 + 17 = (17 - 15) - 3 w:
(17 - 15) - 3 w = 6 (w + 5) - 2 w
17 - 15 = 2:
2 - 3 w = 6 (w + 5) - 2 w
6 (w + 5) = 6 w + 30:
2 - 3 w = 6 w + 30 - 2 w
Grouping like terms, 6 w - 2 w + 30 = (6 w - 2 w) + 30:
2 - 3 w = (6 w - 2 w) + 30
6 w - 2 w = 4 w:
2 - 3 w = 4 w + 30
Subtract 4 w from both sides:
2 + (-3 w - 4 w) = (4 w - 4 w) + 30
-3 w - 4 w = -7 w:
-7 w + 2 = (4 w - 4 w) + 30
4 w - 4 w = 0:
2 - 7 w = 30
Subtract 2 from both sides:
(2 - 2) - 7 w = 30 - 2
2 - 2 = 0:
-7 w = 30 - 2
30 - 2 = 28:
-7 w = 28
Divide both sides of -7 w = 28 by -7:
(-7 w)/(-7) = 28/(-7)
(-7)/(-7) = 1:
w = 28/(-7)
The gcd of 28 and -7 is 7, so 28/(-7) = (7×4)/(7 (-1)) = 7/7×4/(-1) = 4/(-1):
w = 4/(-1)
Multiply numerator and denominator of 4/(-1) by -1:
Answer: w = -4
Step-by-step explanation:
first way by sitting 3 person in one chair
