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Zinaida [17]
3 years ago
10

When a number is doubled, the result is 48. What is the number

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0
24 is the number, you must divide 48 by 2


ddd [48]3 years ago
3 0
The number u looking for is 28
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Find the distance between the two points in simplest radical form.<br> (7,-1) and (9,-9)
storchak [24]

Answer:

\sqrt{68}

Step-by-step explanation:

(7 , -1) = (x1 , y1)

(9 , -9) = (x2 , y2)

distance formula = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

=\sqrt{(9 - 7)^2 + (-9 - (-1))^2}

=\sqrt{2^2 + (-9 + 1)^2}

=\sqrt{4 + (-8)^2}

=\sqrt{4 + 64}

=\sqrt{68}

7 0
3 years ago
Read 2 more answers
Which function has zeros at x=-2 and x=5?
Licemer1 [7]

Answer:

x^{2} - 3x - 10

Step-by-step explanation:

To start, lets form our polynomial factors from our zeroes.

x = -2

x + 2 = 0

x = 5

x - 5 = 0

Now lets put these into factored form by moving them into parenthesis and multiplying them with each other!

(x+2)(x-5)

We can start moving them out! I am going to use FOIL, but you could also use distributive or any other method/property.

x · x = x²

x · -5 = -5x

x · 2 = 2x

2 · 5 = 10

Now lets put our terms into our polynomial function, based on the order of the powers.

x^{2} - 3x - 10

We are done! Hope this helps!

7 0
3 years ago
(4x^2+24x+32)/(2x^2-2x-12)
krek1111 [17]
2 · (x+4)/x-3 Is the answer. I hope it helps.
4 0
3 years ago
D.sqrt(2+x^/2)<br> Solve this question please
lidiya [134]

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

y = \sqrt{4 + a*x^2}

y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

y' = \frac{x*y}{2 + x^2}

replacing y' and y we get:

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

Now we can try to solve this for "a".

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

If we multiply both sides by y(x), we get:

\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}

a*x = \frac{x*(4 + a*x^2)}{2 + x^2}

We can remove the x factor in both numerators if we divide both sides by x, so we get:

a = \frac{4 + a*x^2}{2 + x^2}

Now we just need to isolate "a"

a*(2 + x^2) = 4 + a*x^2

2*a + a*x^2 = 4 + a*x^2

Now we can subtract a*x^2 in both sides to get:

2*a = 4\\a = 4/2 = 2

Then the solution is:

y = \sqrt{4 + 2*x^2}

The correct option is option a.

7 0
3 years ago
The sum of two numbers is 56. the first number is 2/5 of the second number. Let x represent the first number and y represent the
SpyIntel [72]
Hello, 

x= first number
y= second number

their sum is 56, so:
x+y=56

The first number is 2/5 of the second number, so:
x= \frac{2}{5}y

Those are the two equations.
4 0
3 years ago
Read 2 more answers
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