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Ghella [55]
3 years ago
13

Factor this expression. ab + 2a + 3b + 6.

Mathematics
1 answer:
egoroff_w [7]3 years ago
7 0
Factor out the greatest common factor of each group
a(b+2)+3( b+2)
Factor the polynomial by factoring out the greatest common factor, b+2
(b+2)(a+3)
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EXPLAIN HOW YOU WOULD USE REPEATED SUBTRACTION TO FIND 8 DIVIDED BY 2
Zepler [3.9K]
Imagine that you have 8 apples which you want to hand out to 2 people. You want each person to get an equal amount of apples, so you decide to give 2 apples at a time (one apple to each), until you run out or you don't have enough to give each of the 2 people another apple. Notice that each time you give out 2 apples, you have to subtract 2 from the total left over, and each person gets one apple. Let's see what happens:
1. 8-2=6 -- each person now has 1 apple, and there are 6 more to hand out;
2. 8-2-2=4 -- each person now has 2 apples, and there are 4 more to pass out;
3. 8-2-2-2=2 -- each person now has 3 apples, and there are 2 more to distribute;
4. 8-2-2-2-2=0 -- each person now has 4 apples and there are no more apples to pass out.
Then you hand out 8 apples to 2 people and each of the get 4 apples. This meansthat 8÷2=4.




6 0
3 years ago
Read 2 more answers
The end point of GH(line) are G(-2, -7) and H(-8, 7) find the coordinates of the midpoint M
goblinko [34]

Answer:

Step-by-step explanation:

if (x,y)is mid point of two points (x1,y1) ,(x2,y2) then

x=(x1+x2)/2

and y=(y1+y2)/2

coordinates of M are ((-2+(-8))/2,(-7+7)/2)

or are (-5,0)

8 0
3 years ago
Mathhhh helppppppppppppppppppp
Salsk061 [2.6K]
4. C)If two figures are congruent, then they are similar.
If they are congruent them shape and size are the same and hence they are similar

5. Ratio 4/3 smaller side is 21
Multiply to find large side
4/3×21= 28ft D)

6. Width went from 24 to 3 in divide to get ratio
24/3 =8 now divide the length by 8 to find the postcard length
32/8= 4 in A)

8. If they are similar you need to find the ratio y reduces from 8 is similar to 6 so link those 6/8
This is your ratio you can simplify it to 3/4 now y/6 should also = 3/4
Y/6=3/4
Y=18/4= 4.5 C)

9.C)DC

8 0
3 years ago
Read 2 more answers
52 + 6 × (5 − 3) − 10⁄2
GenaCL600 [577]
52+6×2− 2
10
​


2 Simplify
6
×
2
6×2 to
12
12.
52
+
12
−
10
2
52+12−
2
10
​


3 Simplify
10
2
2
10
​
to
5
5.
52
+
12
−
5
52+12−5

4 Simplify
52
+
12
52+12 to
64
64.
64
−
5
64−5

5 Simplify.
59
59
5 0
3 years ago
Read 2 more answers
I need the domain range and function. With an explanation
erastovalidia [21]
<h3>Answers:</h3>

Problem 1

  • Domain = -3 < x \le 3, interval notation (-3, 3]
  • Range = -3 \le y < 3, interval notation [-3, 3)
  • Is it a function? Yes

Problem 2

  • Domain = x \ge -2, interval notation [-2, \infty)
  • Range = All real numbers, interval notation (-\infty, \infty)
  • Is it a function? No

Problem 3

  • Domain = -4 \le x < 3, interval notation [-4, 3)
  • Range = -4 < y \le 3, interval notation (-4, 3]
  • Is it a function? Yes

Problem 4

  • Domain = All real numbers, interval notation (-\infty, \infty)
  • Range = y \le 4, interval notation (-\infty, 4]
  • Is it a function? Yes

==================================================

Explanations:

  1. The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore -3 < x \le 3 which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
  2. The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is x \ge -2 which in interval notation is [-2, \infty). The range is (-\infty, \infty) to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
  3. This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
  4. This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is y \le 4 which is the same as saying (-\infty, 4] in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0
4 years ago
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